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natita [175]
3 years ago
11

Which of the following options results in a graph that shows exponential growth. F(x) = 0.4(3)^x. F(x) = 3(0.5)^x. F(x) = 0.8(0.

9)^x. F(x) = 0.9(5)^-x
Mathematics
1 answer:
Andre45 [30]3 years ago
5 0
f(x)=a^x\\\\if\ a \ \textgreater \  1\ then\ a\ function\ is\ an\ exponential\ growth\ function

f(x)=0.4(3)^x\to a=3 > 1\ OK!\\f(x)=3(0.5)^x\to a=0.5 < 1 :(\\f(x)=0.8(0.9)^x\to a=0.9 < 1 :(\\f(x)=0.9(5)^{-x}=0.9\left(\dfrac{1}{5}\right)^x\to a=\dfrac{1}{5} < 1\ :(

Answer: f(x)=0.4(3)^x
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alex41 [277]

Answer:

Option 2

Step-by-step explanation:

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3 years ago
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In order to determine the average price of hotel rooms in Atlanta, a sample of 64 hotels was selected. It was determined that th
deff fn [24]

Answer:

The decision rule is  

Fail to reject the null hypothesis

The conclusion is  

There is no sufficient evidence to show that the average room price is significantly different from $108.50

Step-by-step explanation:

From the question we are told that

   The sample size is  n = 64

    The average price is  \= x  = \$ 112

    The population standard deviation is  \sigma  = \$ 16

     The level of significance is  \alpha  = 0.05

    The population mean is  \mu = \$ 108.5

The null hypothesis is  H_o :  \mu = 108.50

The alternative hypothesis is  H_a  :  \mu \ne  108.50

Generally the test statistics is mathematically represented as

       z = \frac{\= x - \mu }{ \frac{ \sigma}{\sqrt{n} } }

=>    z = \frac{112 - 108.50 }{ \frac{ 16}{\sqrt{64} } }  

=>    z = 1.75

From the z table  the area under the normal curve to the left corresponding to  1.75  is  

       P( Z >  1.75) = 0.040059

Generally  p-value is mathematically represented as

        p-value = 2 * P( Z >  1.75)

=>     p-value = 2 * 0.040059

=>     p-value = 0.08012

From the values obtained we see that  p-value  > \alpha hence

The decision rule is  

Fail to reject the null hypothesis

The conclusion is  

There is no sufficient evidence to show that the average room price is significantly different from $108.50

 

3 0
3 years ago
The data below shows the average number of text messages sent daily by a group of people: 7, 8, 4, 7, 5, 2, 5, 4, 5, 7, 4, 8, 2,
enot [183]
It all depends. You've given us an incredibly vague question.

The outlier could be a number that's low or quite high. Also, outliers
shouldn't really contribute towards the value of the mean, median or 
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They are called outliers because they are bizarre results or numbers
and should be detached from groups of data. Outliers by definition
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I'd say outliers don't really change anything, unless you actually want
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Large outliers can inflate the value of means, medians and ranges.

Small outliers will invariably deflate the value of means and medians.
3 0
3 years ago
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a bird is flying at a true bearing of 75 degree's at a speed of 40 miles per hour. Write the velocity of the bird as a vector in
Allisa [31]

Answer: V = (10.4 mph, 38.6 mph)

Step-by-step explanation:

The velocity is written as (vx, vy)

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In usual notation, the angles are measured counterclockwise from the positive x-axis.

We know that the angle is 75°, this means that the velocity in the x-axis will be equal to the total velocity of the bird projected in the x-axis (suppose a triangle rectangle, where the velocity is the hypotenuse, the x component is a cathetus and the y component is other cathetus)

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vy = 40mph*sin(75°) = 38.6mph

Then the vector of velocity is V = (10.4 mph, 38.6 mph)

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Naya [18.7K]
First let’s call the square shape A and the rectangle shape B.

To find the area of shape A you do 24 x 24 = 576cm squared

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576 + 960 = 1536cm squared
4 0
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