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borishaifa [10]
2 years ago
5

Please help me with this question. I will mark you brainliest. ​

Mathematics
1 answer:
solong [7]2 years ago
4 0

<u>Answer:</u>

<em>Option D : $153</em>

<u>This is how I got that:</u>

9:30 AM to 1:15 PM = 3 hours and 45 minutes

The first hour charges $15 and for the remaining 2 hours and 45 minutes

Mr. Anand is charged 36$. Remember it says that each additional hour <em>or part thereof, </em>so the 2 hours and 45 minutes is considered 3 hours.

So our total for one paddle boat is <u>$51 </u>

<u />

But Mr. Anand hired <em>three</em> boats so we simply times 51 by 3 and get our solution to the problem:

<u>Mr. Anand must pay $153 or Option D</u>

<u></u>

<em>~That's All Folks~</em>

<em>-Siascon</em>

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With a family bowling pass, families can bowl for $4 per game . The pass cost $10 per year. Use equation , a table and a graph t
Klio2033 [76]

Answer:

Part a) a=4g+10 (see the explanation)

Part b) see the explanation

Part c) The graph in the attached figure

Step-by-step explanation:

<u><em>The complete question is</em></u>

With a family bowling pass, families can bowl for $4 per game. The pass costs $10 per year. Use an equation, a table, and a graph to explain the relationship between the total amount of money spent on bowling in a year, a, and the number of games a family plays in a year, g. Part A Use words and an equation to represent this problem. Part B Create a table to show values for g and a. Part C Use the values from your table to draw a graph.

Part A) Use words and an equation to represent this problem

Let

a ----> the total amount of money spent on bowling in a year

g ---> the number of games a family plays in a year

we know that

The linear equation in slope intercept form is equal to

a=mg+b

where

m is the slope or unit rate

b is the a-intercept or initial value

In this problem we have

m=\$4\ per\ game

b=\$10

substitute

a=4g+10

Part b) Create a table to show values for g and a

Assume different values of g and calculate the corresponding values of a

For g=0 ----> a=4(0)+10=\$10

For g=1 ----> a=4(1)+10=\$14

For g=2 ----> a=4(2)+10=\$18

For g=3 ----> a=4(3)+10=\$22

For g=4 ----> a=4(4)+10=\$26

The table is

\left[\begin{array}{ccc}g&a\\0&10\\1&14\\2&18\\3&22\\4&26\end{array}\right]

Part c) Use the values from your table to draw a graph

we have the ordered pairs

(0,10),(1,14),(2,18),(3,22),(4,26)

Plot the ordered pairs and join them to graph the line

The graph in the attached figure

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