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4 years ago

What is the m12 in matrix m = [874][205]

2 answers:

5 0

The answer is 7 I just took the practice quiz. http://www.jiskha.com/display.cgi?id=1447027615. All the answers are on here if you or anyone needs them

Archy [21]4 years ago

3 0

We have been given the matrix m as m = [874][205].

We can rewrite this matrix as

$m=\begin{pmatrix}8 &7&4\\2&0&5 \\\end{pmatrix}\\$

Now, we need to the find $m_{12}$

It means we need to find the entity that is present in the first row and the second column.

From the above matrix, we can see that 7 is in the first row and the second column.

Therefore, we have

$m_{12}= 7$

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Does each relation reprsent a fuction? choose yes or no

mariarad [96]

Answer:

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3 0

3 years ago

20 POINTS PLEASE HELP

Temka [501]

1. It's in point-slope form right now
y - 7 = -x - 4
x + y = 3

2. Find the slope through (y2-y1) / (x2-x1)
The slope is 3.
Use the point slope formula: y - 9 = 3 (x - 8)
y - 9 = 3x - 24
y = 3x - 15

3. a. standard form
b. point-slope
c. slope-intercept
d. standard

5. Use point-slope: y - 8 = 6 (x - 3)
y - 8 = 6x - 18
-6x + y = -10

6 0

3 years ago

HELP FAST ALL OF MY POINTS TO BE GIVEN TO YOU

gogolik [260]

Answer:

C > 9

Step-by-step explanation:

3 0

3 years ago

If x^2y-3x=y^3-3, then at the point (-1,2), (dy/dx)?

zavuch27 [327]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2866883

_______________

   dy
Find —— for an implicit function:
    dx

x²y – 3x = y³ – 3

First, differentiate implicitly both sides with respect to x. Keep in mind that y is not just a variable, but it is also a function of x, so you have to use the chain rule there:

$\mathsf{\dfrac{d}{dx}(x^2 y-3x)=\dfrac{d}{dx}(y^3-3)}\\\\\\
\mathsf{\dfrac{d}{dx}(x^2 y)-3\,\dfrac{d}{dx}(x)=\dfrac{d}{dx}(y^3)-\dfrac{d}{dx}(3)}$

Applying the product rule for the first term at the left-hand side:

$\mathsf{\left[\dfrac{d}{dx}(x^2)\cdot y+x^2\cdot \dfrac{d}{dx}(y)\right]-3\cdot 1=3y^2\cdot \dfrac{dy}{dx}-0}\\\\\\
\mathsf{\left[2x\cdot y+x^2\cdot \dfrac{dy}{dx}\right]-3=3y^2\cdot \dfrac{dy}{dx}}$

   dy
Now, isolate —— in the equation above:
   dx

$\mathsf{2xy+x^2\cdot \dfrac{dy}{dx}-3=3y^2\cdot \dfrac{dy}{dx}}\\\\\\
\mathsf{2xy+x^2\cdot \dfrac{dy}{dx}-3-3y^2\cdot \dfrac{dy}{dx}=0}\\\\\\
\mathsf{x^2\cdot \dfrac{dy}{dx}-3y^2\cdot \dfrac{dy}{dx}=-\,2xy+3}\\\\\\
\mathsf{(x^2-3y^2)\cdot \dfrac{dy}{dx}=-\,2xy+3}$

$\mathsf{\dfrac{dy}{dx}=\dfrac{-\,2xy+3}{x^2-3y^2}\qquad\quad for~~x^2-3y^2\ne 0}$

Compute the derivative value at the point (– 1, 2):

x = – 1 and y = 2

$\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=\dfrac{-\,2\cdot (-1)\cdot 2+3}{(-1)^2-3\cdot 2^2}}\\\\\\
\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=\dfrac{4+3}{1-12}}\\\\\\
\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=\dfrac{7}{-11}}\\\\\\\\ \therefore~~\mathsf{\left.\dfrac{dy}{dx}\right|_{(-1,\,2)}=-\,\dfrac{7}{11}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

Tags: <em>implicit function derivative implicit differentiation chain product rule differential integral calculus</em>

6 0

3 years ago

The length of a field in feet is a function f(n) of the length nin yards. Write a function rule for this situation.

qwelly [4]

Given:

The length of field is n yards.

The length of a field in feet is a function f(n).

To find:

The function rule for this situation.

Solution:

We know that,

1 yard = 3 feet

Using this conversion, we get

n yard = 3n feet

The length of field is n yards. So, the length of the field is 3n feets.

The length of a field in feet is a function f(n). So,

$f(n)=3n$

Therefore, the required function rule for this situation is $f(n)=3n$ .

5 0

3 years ago