Answer:
87.29%
Step-by-step explanation:
Given: Mean= 68.8 inches
Standard deviation= 2.8 inches
Now, finding the percent of the men in the sample were greater than 72 inches.
We know, z-score= 
z-score= 
⇒ z-score= 
∴ z-score= 1.14
Next, using normal distribution table to find percentage.
Coverting 0.8729 into percentage= 
We get the percentage as 87.29%
Hence, 87.29% of the men in the sample were greater than 72 inches.
Answer:
the norm of V = =11.357816691601..
Step-by-step explanation:




1800
LCM of 10 and 15 = 30
LCM of 6 and 20 = 60
30(60) = 1800
1/2 it's a fifty fifty unless the guys are complete idiots