Question

suppose that a dominant allele (P) codes for a polka-dot tail and a recessive allele (p) codes for a solid colored tail. In addition, suppose that a dominant allele (L) codes for long eyelashes and a recessive allele (l) codes for short eyelashes. If two individuals heterozygous for both traits (tail color and eyelash length) mate, what's the probability of the phenotypic combinations of the offspring? A. 9:3:3:1 ratio (9 polka-dot tails and long eyelashes, 3 polka-dot tails and short eyelashes, 3 solid tails and long eyelashes, 1 solid tail and short eyelash) B. 1:1 ratio (half are polka-dot tails and long eyelashes; half are solid tails and short eyelashes) C. 1:1 ratio (half are polka-dot tails and short eyelashes; half are solid tails and long eyelashes) D. 9:3:3:1 ratio (9 polka-dot tails and short eyelashes, 3 polka-dot tails and long eyelashes, 3 solid tails and short eyelashes, 1 solid tail and long eyelash)

Answer 1

Letter for polka dots tail (dominant) = P
letter for solid color tail(recessive) = p

Letter for long eyelashes (dominant) = L
letter for short eyelashes (recessive) = l

Heterozygous for both genes= PpLl
Cross = PpLl x PpLl

The answer is A. 9:3:3:1 ratio
9 polka-dot tails and long eyelashes
3 polka-dot tails and short eyelashes
3 solid tails and long eyelashes
1 solid tail and short eyelash