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3 years ago

PLEASE HELP!! algebra 2

Mathematics

1 answer:

Debora [2.8K]3 years ago

5 0

Answer:

your answer is D

Step-by-step explanation:

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Consider the following scenario:

Sladkaya [172]

Answer:

1. P(C AND D) = 0.3

2. (C.) C and D are not mutually exclusive because P(C AND D) ≠ 0

3. (A.) The events are not independent because P(C | D) ≠ P(C)

4.P(D | C) = 0.5

Step-by-step explanation:

• Let P(C) = 0.4

• Let P(D) = 0.5

• Let P(C | D) = 0.6

1.) Find P(C AND D).

$P(C | D) = \frac{P(C n D)}{P(D)} \\P(C n D) = P(C | D) * P(D)\\P(C n D) = 0.6 * 0.5\\P(C n D) = 0.3$

2.) Events can be mutually exclusive meaning the both event cannot happen at the same time. So, P(A and B) = 0

3.) Events can be "Independent", meaning each event is not affected by any other events.

4.) Find P(D | C)

$P(D | C) = \frac{P (D n C)}{P(C)}\\P(D n C) = 0.5 * 0.4 = 0.2\\P(D | C) = \frac{0.2}{0.4}\\P(D | C) = 0.5$

6 0

4 years ago

Consider circle E. A B 26 D E F What is the mBC ? mBC Please help

RSB [31]

Step-by-step explanation:

< AEB + < BEC = 180° {BEING LINEAR PAIR }

26° + < BEC = 180°

< BEC = 180° - 26°

< BEC = 154°

ARC BC = < BEC ( relation between arc and central angle)

Arc BC = 154°

Hope it will help :)

8 0

3 years ago

Plz help, The graph of y = f(x) is shown below. What are all of the real solutions of f(x) = 0?

8_murik_8 [283]

Answer:

The real solutions of f(x)=0 are: 0, 2, 5, 6

Step-by-step explanation:

We are given:

The graph of y = f(x)

We need to find all of the real solutions of f(x) = 0?

By looking at the graph we need to find the values of y when x =0

Looking at the graph, when x=0 we get

0, 2,5 and 6

So, the real solutions of f(x)=0 are: 0, 2, 5, 6

I am attaching the figure, that determines the answers.

8 0

3 years ago

Give the slope and the y-intercept of the line

worty [1.4K]

It would be y=Mx+b that is the answer

5 0

3 years ago

Which expression is equivalent to square root 55x^7y6/11x^11y^8

Novay_Z [31]

Answer:

$\large\boxed{\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\dfrac{\sqrt5}{x^2y}}$

Step-by-step explanation:

$\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\sqrt{\dfrac{55}{11}\cdot\dfrac{x^7}{x^{11}}\cdot\dfrac{y^6}{y^8}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=\sqrt{5x^{7-11}y^{6-8}}=\sqrt{5x^{-4}y^{-2}}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt5\cdot\sqrt{x^{-4}}\cdot\sqrt{y^{-2}}=\sqrt5\cdot\sqrt{x^{(-2)(2)}}\cdot\sqrt{y^{(-1)(2)}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt5\cdot\sqrt{(x^{-2})^2}\cdot\sqrt{(y^{-1})^2}\qquad\text{use}\ \sqrt{a^2}=a$

$=\sqrt5\cdot x^{-2}\cdot y^{-1}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\to a^{-1}=\dfrac{1}{a}\\\\=\sqrt5\cdot\dfrac{1}{x^2}\cdot\dfrac{1}{y}=\dfrac{\sqrt5}{x^2y}$

6 0

3 years ago