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gregori [183]
2 years ago
5

Find the quotient of

%20%28x%20-%203%29%7D" id="TexFormula1" title="\frac{(x^{3} - 2x^{2} + 6x + 3)}{ (x - 3)}" alt="\frac{(x^{3} - 2x^{2} + 6x + 3)}{ (x - 3)}" align="absmiddle" class="latex-formula"> using long division
Mathematics
1 answer:
DedPeter [7]2 years ago
7 0
I can’t really do long division on a phone so, extended techniques are required.

(x^3 - 2x^2 + 6x + 3)/(x-3)

= (x^3 - 3x^2 + (x^2 - 6x + 9)+ 12x - 6)/(x-3)

= (x^2(x-3) + (x-3)^2 + 6(2x - 1))/x-3

= x^2 + x - 3 + 6(2x - 1)/(x-3)

or

= x^2 + x - 3 remainder 12x - 6


or, in the form p(x) = q(x)d(x) + r(x):


(x^3 - 2x^2 + 6x + 3) = (x^2 + x - 3)(x - 3) + (12x - 6)

which implies that the quotient q(x) = (x^2 + x - 3) and remainder r(x) = 12x - 6
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mariarad [96]

Answer:

f(10) = 1147.25

Step-by-step explanation:

Given

f(-1.5) = 26

f(5.5) = 7

Required

f(10)

An exponential function is represented as:

f(x) = ab^x

f(-1.5) = 26 impleies that:

26 = ab^{-1.5} --- (1)

f(5.5) = 7 implies that

7 = ab^{5.5} --- (2)

Divide (2) by (1)

26/7 = ab^{-1.5}/ab^{5.5}

3.71429 = b^{-1.5+5.5}

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Take 4th root

b = 1.39

Substitute b = 1.39 in 26 = ab^{-1.5}

26 = a * 1.39^{-1.5}

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Solve for (a)

a = 26/0.6102

a = 42.61

f(10) is calculated as:

f(10) = ab^{10}

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Step-by-step explanation:

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