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nikklg [1K]
3 years ago
6

What is the height of a triangle that has an area of 60 yd squared and a base with a length of 12 yd

Mathematics
2 answers:
zmey [24]3 years ago
8 0
The answer would be 0.4yd
3241004551 [841]3 years ago
4 0
The answer is:  " 10 yd. " . 
_______________________________________________________
The height of the triangle is:  " 10 yd " .
_______________________________________________________
Explanation:
_______________________________________________________
The formula for the area, "A", of a triangle is:

          →   " A = (b * h) / 2  " ; 

in which:  " A = area (in square units;  in this case;  "yd² " ; 
                       
                      = " 60 yd² " {given} ; 

                  "b = base length = 12 yd" {given} ; 

                  "h = [perpendicular] height ; for which we shall solve;
_______________________________________________________

 →  A = (b * h) / 2 ;  

 → Rearrange the equation to isolate "h" on one side of the equation; since we need to solve for "h" (height) ; 

→  Multiply each side of the equation by "2" ; 

→  2 * A = 2 * [ (b * h) / 2 ] ;

to get:

→  2A  = b * h ; 

↔  b * h = 2A ; 

Divide each side of the equation by "b" ; 
          to isolate "h" on one side of the equation; 

→  (b * h) / b  =  2A / b ; 

→  h = 2A / b ; 

Now, plug in our given values for "A" and "b" ;  
    to solve for "h" ; 

→  h = (2* 60 yd²) / (12 yd) ; 

         = (120 yd²) / (12 yd). 

         = 10 yd.

→  h = 10 yd.
_______________________________________________________
The answer is:  " 10 yd. " . 
_______________________________________________________
The height of the triangle is:  " 10 yd " .
_______________________________________________________
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The weight of the chocolate and Hershey Kisses are normally distributed with a mean of 4.5338 G and a standard deviation of 0.10
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For the bell-shaped graph of the normal distribution of weights of Hershey kisses, the area under the curve is 1, the value of the median and mode both is 4.5338 G and the value of variance is 0.0108.

In the given question,

The weight of the chocolate and Hershey Kisses are normally distributed with a mean of 4.5338 G and a standard deviation of 0.1039 G.

We have to find the answer of many question we solve the question one by one.

From the question;

Mean(μ) = 4.5338 G

Standard Deviation(σ) = 0.1039 G

(a) We have to find for the bell-shaped graph of the normal distribution of weights of Hershey kisses what is the area under the curve.

As we know that when the mean is 0 and a standard deviation is 1 then it is known as normal distribution.

So area under the bell shaped curve will be

\int\limits^{\infty}_{-\infty} {f(x)} \, dx= 1

This shows that that the total area of under the curve.

(b) We have to find the median.

In the normal distribution mean, median both are same. So the value of median equal to the value of mean.

As we know that the value of mean is 4.5338 G.

So the value of median is also 4.5338 G.

(c) We have to find the mode.

In the normal distribution mean, mode both are same. So the value of mode equal to the value of mean.

As we know that the value of mean is 4.5338 G.

So the value of mode is also 4.5338 G.

(d) we have to find the value of variance.

The value of variance is equal to the square of standard deviation.

So Variance = (0.1039)^2

Variance = 0.0108

Hence, the value of variance is 0.0108.

To learn more about normally distribution link is here

brainly.com/question/15103234

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3 0
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Answer:

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If A = (2, 3) then a dilation of scale factor 2 means that the x and y coordinates are multiplied by 2, so x = 2 x 2 = 4  and y = 3 x 2 = 6, so A' = (4, 6)

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Finally, at N = 21, again 33.33%.  N = 22 and N = 23 are both greater than 30%.  As we continue this, for any N after 20, we will always be greater than 30%.

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