Answer:
205K
Explanation:
The following were obtained from the question:
n = 4moles
P = 5.6atm
V = 12L
R = 0.082atm.L/Kmol
T =?
PV = nRT
T = PV/nR
T = (5.6 x 12)/ (4 x 0.082)
T = 205K
They are an example of colloids .....
Answer:0.8742j/g°C
Explanation: SOLUTION
GIVEN
length of bar=1.25m
mass 382g
temperature= 20°C to 288°C
Q=89300J
Specific Heat Capacity will be calculated using
Q=mC∆T
where
C = specific heat capacity
Q = heat
m = mass
Δ T = change in temperature
C=Q/ m∆T
=89300/382X(288-20.6)
=0.8742j/g°C
An ambient pressure of 1 atm
