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butalik [34]
3 years ago
11

1.25 x 1025 molecules of glucose (C H202) is how many moles of glucose?

Chemistry
1 answer:
ExtremeBDS [4]3 years ago
5 0

Answer:

1281.25 Moles of glucose

Explanation:

Multiply 1.25x1025= 1281.25

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Limitation for osmosis experiment
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What was the question here?
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2 years ago
Two rigid transformations are used to map TriangleJKL to TriangleMNQ. The first is a translation of vertex L to vertex Q. What i
Elodia [21]

Answer:

The second transformation is a rotation around (point) L.

Explanation:

Generally, a rigid transformation is used to change only the position of a figure while the shape remains the same. In order to map a triangle (ΔJKL) to another triangle (ΔMNQ), two rigid transformations were employed. In the first transformation, the vertex L was mapped to the vertex Q. Therefore, the second transformation will definitely involve the rotation around (point) L. This will complete the two rigid transformations.

7 0
3 years ago
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Which states of water can you find in your home? Explain.
rosijanka [135]

Answer:

all

Explanation:

water vapor is everywhere

ice is in the freezer and hopefully you drink water.  

5 0
3 years ago
What is the delta H fusion used to calculate volume of a liquid frozen that produces 1 kg of energy?
gulaghasi [49]

Answer:

The correct option is C. 1 kJ x 1/ΔHfus x g/mol x ml/g liquid

Explanation:

The change in enthalpy of fusion (ΔHfus) has units of energy divided into moles of substance:

ΔHfus = energy/mol of substance = J/mol or KJ/mol

Thus, we multiply the kJ of energy produced by the inverse of ΔHfus (in kJ/mol) we obtain the moles of substance:

energy (kJ) x 1/ΔHfus (mol/kJ) = moles of substance(mol)

Then, if we multiply the moles of substance by the molecular weight of the substance (in g/mol) we obtain the grams:

moles of substance(mol) x molecular weight (g/mol) = grams of substance (g)

Finally, if we multiply the grams of substance (in g) by the density of the substance (in g/ml) we obtain the volume (in ml):

grams of substance (g) x 1/density (ml/g) = volume (ml)

We combine all these parts to obtain the equation for the volume required to produce 1 kJ of energy:

energy (kJ) x 1/ΔHfus (mol/kJ) x molecular weight (g/mol) x 1/density (ml/g)

Therefore, the correct option is:

C → 1 kJ x 1/ΔHfus x g/mol x ml/g liquid

5 0
3 years ago
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Describe the chemical reaction based on the chemical equation below. Also, explain whether the equation is balanced.
liubo4ka [24]

Answer:

The balanced equation is: 4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(I)

4 moles of ammonia need 5 moles of oxygen to react, in order to produce 6 moles of water and 4 moles of nitrogen oxide.

Explanation:

NH₃(g) + O₂(g) → NO(g) + H₂O(I)

That is the unbalanced equation.

Ratio is 1:1, so 1 mol of ammonia and 1 mol of oxygen may react to produce 1 mol of NO and 1 mol of water

First of all we need to balance. Let's count the atoms:

In reagent side, we have 3 H and in product side there are 2H, we can add a 3, so now we have 6 H. Therefore, the reagent side must have 2 in front of the ammonia. In both sides we have 6 H

Now, that we added a 2 in the ammonia, we have 2N, so we have to add 2 to NO in the product side.

Let's count the oxygen in the product side, 5. We must add 5/2 in the reactant side. But chemical equations usually do not have rational numbers, that's why we multiply x2, all the stoichiometry.

The balanced equation is: 4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(I)

4 moles of ammonia need 5 moles of oxygen to react, in order to produce 6 moles of water and 4 moles of nitrogen oxide.

3 0
3 years ago
Read 2 more answers
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