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3 years ago

Boyles Law-

Chemistry

1 answer:

My name is Ann [436]3 years ago

5 0

Answer:

Boyles Law-

Variables that change: volume and pressure

Variables that remain constant: Temperature

Charles Law-

Variables that change: volume and temperature

Variables that remain constant: pressure

Explanation:

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Convert 25 liters per hour to milliliters per second.

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Answer:

6.94444

Explanation:

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Are assorted jelly beans heterogeneous or homogeneous

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Heterogeneous, which means that they are not evenly combined.

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3 years ago

A compound that contains only carbon, hydrogen, and oxygen is 58.8% C and 9.87% H by mass. What is the empirical formula of this

Dmitry [639]

Answer: The empirical formula of the compound becomes $C_5H_{10}O_2$

Explanation:

The empirical formula is the chemical formula of the simplest ratio of the number of atoms of each element present in a compound.

Let the mass of the compound be 100 g

Given values:

% of C = 58.8%

% of H = 9.87%

% of O = [100 - 58.8 - 9.87] = 31.33%

Mass of C = 58.8 g

Mass of H = 9.87 g

Mass of O = 31.33 g

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Molar mass of C = 12 g/mol

Molar mass of H = 1 g/mol

Molar mass of O = 16 g/mol

Putting values in equation 1, we get:

$\text{Moles of C}=\frac{58.8g}{12g/mol}=4.9 mol$

$\text{Moles of H}=\frac{9.87g}{1g/mol}=9.87 mol$

$\text{Moles of O}=\frac{31.33g}{16g/mol}=1.96mol$

Step 2: Calculating the mole ratio of the given elements.

Calculating the mole fraction of each element by dividing the calculated moles by the least calculated number of moles that is 1.96 moles

$\text{Mole fraction of C}=\frac{4.9}{1.96}=2.5$

$\text{Mole fraction of H}=\frac{9.87}{1.96}=5.03\approx 5$

$\text{Mole fraction of O}=\frac{1.96}{1.96}=1$

Converting the mole fraction into whole numbers by multiplying them with 2.

$\text{Mole fraction of C}=2.5\times 2=5$

$\text{Mole fraction of H}=5\times 2=10$

$\text{Mole fraction of O}=1\times 2=2$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 5 : 10 : 2

Hence, the empirical formula of the compound becomes $C_5H_{10}O_2$

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3 years ago

Hexane and hexene are hydrocarbon compounds from different homologous series. the combustion of these two compounds produce diff

AURORKA [14]

Answer:

Percentage of carbon of alkene is higher compared to the alkane that has the same number of carbon per molecule. Because of this, combustion of alkene will produce more sooty flame compared to their corresponding alkane and because Alkenes have a higher percentage of carbon compared to their corresponding alkane.

Explanation:

Relative atomic mass : C= 12 and H=1

Percentage of Carbon Hexane (C6H14)

Percentage of Carbon = 83.7 percent

6(12) x 6(12) +14(1) x 100 percent= 83.7 percent

Percentage of Carbon Hexene = 85.7 percent

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4 years ago

Which is bigger 1,500 ml or 1.5 l

nordsb [41]

It's a trick question; they're the same. 1000mL = 1L

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