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Irina-Kira [14]
4 years ago
7

What the difference in temperature is

Mathematics
1 answer:
Alexandra [31]4 years ago
6 0
The answer would be a positive 15.1 or +15.1 because the positive number is greater than the negative which would make your answer positive, thats why you got it wrong :) 
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kipiarov [429]

The correct answer would be B

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4 years ago
List domain and Range in interval notation, then decide if it is a function or not.
oksano4ka [1.4K]
Domain are for x-values so [0,3] and range are y-values so [2,-2]. It is not a function because there are multiple x-values for y-values. The only thing I am not sure about is whether to use brackets [ ] and/or parentheses ( ) because the graph does not use circles. Hope this helped!
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3 years ago
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Soloha48 [4]
You're trying to find constants a_0,a_1,a_2 such that \hat y=a_0+a_1\hat x+a_2{\hat x}^2. Equivalently, you're looking for the least-square solution to the following matrix equation.


\underbrace{\begin{bmatrix}1&6&6^2\\1&3&3^2\\\vdots&\vdots&\vdots\\1&9&9^2\end{bmatrix}}_{\mathbf A}\underbrace{\begin{bmatrix}a_0\\a_1\\a_2\end{bmatrix}}_{\mathbf x}=\underbrace{\begin{bmatrix}100\\110\\\vdots\\70\end{bmatrix}}_{\mathbf b}

To solve \mathbf{Ax}=\mathbf b, multiply both sides by the transpose of \mathbf A, which introduces an invertible square matrix on the LHS.

\mathbf{Ax}=\mathbf b\implies\mathbf A^\top\mathbf{Ax}=\mathbf A^\top\mathbf b\implies\mathbf x=(\mathbf A^\top\mathbf A)^{-1}\mathbf A^\top\mathbf b

Computing this, you'd find that

\mathbf x=\begin{bmatrix}a_0\\a_1\\a_2\end{bmatrix}\approx\begin{bmatrix}121.119\\-3.786\\-0.175\end{bmatrix}

which means the first choice is correct.
8 0
4 years ago
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Answer:

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Step-by-step explanation:

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Translation means you are shifting the line either up or down.
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