If $860 is invested for one year at 11% simple interest how much interest is earned

Taking a test will mark braniniliest

Vlad [161]

Answer:

whats the question?

8 0

2 years ago

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line pass through the line (-3, -7.5)tahila determined that the equation of line n is y=0.5x explain the error tahila made while

Tasya [4]

The equation of the line will be (assuming the y-intercept equal to zero):

y = 2.5*x

<h3>What is Tahila's mistake?</h3>

We know that we have a linear equation of the form:

y = a*x + b

Such that we know that the line passes through (-3, -7.5), notice that the proposed equation is:

y = 0.5*x

If you evaluate that in -3, you get:

y = 0.5*-3 = -1.5

So this line does not pass through (-3, -7.5).

If we assume that b = 0 in the linear equation, then we can find the value of a as:

-7.5 = a*-3

a = 7.5/3 = 2.5

Then the linear equation is:

y = 2.5*x

If you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ1

4 0

1 year ago

If y varies directly as x, and y is 18 when x is 5, which expression can be used to find the value of y when x is 11?

Leokris [45]

Answer: The value of y is 39.6 when x = 11 and the required expression is y(11) = 39.6

Step-by-step explanation:

Since we have given that

y varies directly as x.

If y = 18, when x = 5.

So, we need to find the value of y when x is 11.

According to question, we get that

$\dfrac{y}{x}=\dfrac{18}{5}=\dfrac{y}{11}\\\\18\times 11=5y\\\\198=5y\\\\\dfrac{198}{5}=y\\\\y=39.6$

Hence, the value of y is 39.6 when x = 11 and the required expression is y(11) = 39.6

5 0

2 years ago

Clark and Lana take a 30-year home mortgage of $128,000 at 7.8%, compounded monthly. They make their regular monthly payments fo

svp [43]

Answer:

Step-by-step explanation:

From the given information:

The present value of the house = 128000

interest rate compounded monthly r = 7.8% = 0.078

number of months in a year n= 12

duration of time t = 30 years

To find their regular monthly payment, we have:

$PV = P \begin {bmatrix} \dfrac{1 - (1 + \dfrac{r}{n})^{-nt}}{\dfrac{r}{n}} \end {bmatrix}$

$128000 = P \begin {bmatrix} \dfrac{1 - (1 + \dfrac{0.078}{12})^{- 12*30}}{\dfrac{0.078}{12}} \end {bmatrix}$

128000 = 138.914 P

P = 128000/138.914

P = $921.433

∴ Their regular monthly payment P = $921.433

To find the unpaid balance when they begin paying the $1400.

when they begin the payment ,

t = 30 year - 5years

t= 25 years

$PV= 921.433 \begin {bmatrix} \dfrac{1 - (1 - \dfrac{0.078}{12})^{25*30}}{\dfrac{0.078}{12}} \end {bmatrix}$

PV = $121718.2714

C) In order to estimate how many payments of $1400 it will take to pay off the loan, we have:

$121718.2714 = \begin {bmatrix} \dfrac{1300 (1 - \dfrac{12.078}{12}))^{-nt}}{\dfrac{0.078}{12}} \end {bmatrix}$

$121718.2714 = 200000 \begin {bmatrix} (1 - \dfrac{12.078}{12}))^{-nt} \end {bmatrix}$

$\dfrac{121718.2714}{200000 } = \begin {bmatrix} (1 - \dfrac{12.078}{12}))^{-nt} \end {bmatrix}$

$0.60859 = \begin {bmatrix} (1 - \dfrac{12}{12.078}))^{nt} \end {bmatrix}$

$0.60859 = (0.006458)^{nt}$

$nt = \dfrac{0.60859}{0.006458}$

nt = 94.238 payments is required to pay off the loan.

How much interest will they save by paying the loan using the number of payments from part (c)?

The total amount of interest payed on $921.433 = 921.433 × 30(12) years

= 331715.88

The total amount paid using 921.433 and 1300 = (921.433 × 60 )+( 1300 + 94.238)

= 177795.38

The amount of interest saved = 331715.88 - 177795.38

The amount of interest saved = $153920.5

6 0

3 years ago

7/8 + ___ = 1 what is the missing numbers

Bezzdna [24]

the missing number is 1/8 i hope this helps chu

4 0

3 years ago