All categories

3 years ago

Which fraction is equivalent to 1/4? A.6/18 b.12/60 c.25/100 d.20/100

Mathematics

2 answers:

fredd [130]3 years ago

6 0

Answer:

c. 25/100

Step-by-step explanation:

The given fraction is 1/4.

Here we need to find the equivalent to 1/4.

It c. 25/100

Let me explain.

Multiply 1/4 by 25 both the numerator and the denominator.

1/4 *25/25 = 1*25 / 4*25

= 25/100

All other fractions are not equivalent to 1/4

Answer: c. 25/100

Thank you.

rusak2 [61]3 years ago

5 0

Answer:

The correct answer is option C. 25/100

Step-by-step explanation:

The given fraction is 1/4

Check each option

Option A:

6/18 = 1/3 (common factor is 3)

Option B:

12/60 = 1/5 (common factor is 12)

Option C:

25/100 = 1/4 (common factor is 25)

Option D:

20/100 = 1/5 (common factor is 5)

Therefore the correct answer is option C. 25/100

You might be interested in

there are 6 brown, 5 blue, and 2 orange marbles in a hat what is the probability of picking 2 orange marbles in a row without re

Bess [88]

You have a probability of 7% to pick out the first orange marble then you have a probability of 8% to pick out the second orange.

4 0

2 years ago

20 POINTS AND BRAINLIEST !! PLEASE ANSWER THIS QUESTION !!

Elenna [48]

A
(X-7)(x-4) -> x^2 -11x + 28
Multiply that by the 2 and you get the original equation!

5 0

3 years ago

Please look at photo and help me I will mark who ever is first

maksim [4K]

Answer:

a = 9

Step-by-step explanation:

you can simplify the proportion to:

$\frac{a}{24} =\frac{3}{8}$

use cross- multiplication

8a = 72

a = 9

5 0

2 years ago

The world population at the beginning of 1980 was 4.5 billion. Assuming that the population continued to grow at the rate of app

AfilCa [17]

Answer:

$Q(t) = 4.5(1.013)^{t}$

The world population at the beginning of 2019 will be of 7.45 billion people.

Step-by-step explanation:

The world population can be modeled by the following equation.

$Q(t) = Q(0)(1+r)^{t}$

In which Q(t) is the population in t years after 1980, in billions, Q(0) is the initial population and r is the growth rate.

The world population at the beginning of 1980 was 4.5 billion. Assuming that the population continued to grow at the rate of approximately 1.3%/year.

This means that $Q(0) = 4.5, r = 0.013$

$Q(t) = Q(0)(1+r)^{t}$

$Q(t) = 4.5(1.013)^{t}$

What will the world population be at the beginning of 2019 ?

2019 - 1980 = 39. So this is Q(39).

$Q(t) = 4.5(1.013)^{t}$

$Q(39) = 4.5(1.013)^{39} = 7.45$

The world population at the beginning of 2019 will be of 7.45 billion people.

6 0

3 years ago

The problem of matching aircraft to passenger demand on each flight leg is called the flight assignment problem in the airline i

Darina [25.2K]

Answer:

Step-by-step explanation:

Given that the demand for the 6 p.m. flight from Toledo Express Airport to Chicago's O'Hare Airport on Cheapfare Airlines is normally distributed with a mean of 132 passengers and a standard deviation of 42

Let X be the no of passengers who report

X is N(132, 42)

Or Z is $\frac{x-132}{42}$

a) Suppose a Boeing 757 with a capacity of 183 passengers is assigned to this flight.

the probability that the demand will exceed the capacity of this airplane

= $P(X>183) = P(Z>1.21) =$

$=0.5-0.3869\\=0.1131$

b) the probability that the demand for this flight will be at least 80 passengers but no more than 200 passengers

= $P(80\leq x\leq 200)\\= P(-1.23\leq z\leq 1.62)\\$

=0.4474+0.3907

=0.8381

c) the probability that the demand for this flight will be less than 100 passengers

$=P(x$

d) If Cheapfare Airlines wants to limit the probability that this flight is overbooked to 3%, how much capacity should the airplane that is used for this flight have? passengers

= $P(Z>c)=0.03\\c=1.88\\X=132+1.88(42)\\=210.96$

e) 79th percentile of this distribution

= $132+0.81(42)\\= 166.02$

7 0

3 years ago