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Tems11 [23]
3 years ago
9

An article in an educational journal discussing a non-conventional high school reading program reports a 95% confidence interval

of (520 , 560) for the average score on the reading portion of the SAT. The study was based on a random sample of 20 students and it was assumed that SAT scores would be approximately normally distributed. Determine the margin of error associated with this confidence interval.
Mathematics
1 answer:
Maksim231197 [3]3 years ago
6 0

Answer:

The margin of error associated with this confidence interval is 20

Step-by-step explanation:

A confidence interval has two bounds, a lower bound and an upper bound. The interval is symmetric, which means that the margin of error is the difference between these two bounds(upper - lower), divided by 2.

In this problem, we have that:

Lower bound: 520

Upper bound: 560

Determine the margin of error associated with this confidence interval.

(560 - 520)/2 = 20

The margin of error associated with this confidence interval is 20

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Consider the relationship between the number of bids an item on eBay received and the item's selling price. The following is a s
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Answer:

Let's assume the following data:

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Number of Bids (Y) 12 13 15 16 18

For our case we have this:

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Step-by-step explanation:

Previous concepts

The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.

Solution to the problem

And in order to calculate the correlation coefficient we can use this formula:  

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

Let's assume the following data

Price in Dollars (X) 26 29 32 38 47

Number of Bids (Y) 12 13 15 16 18

For our case we have this:

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r=\frac{5(2623)-(172)(74)}{\sqrt{[5(6194) -(172)^2][5(1118) -(74)^2]}}=0.974  

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