We can solve this by finding one of the numbers first Let the smaller number be y. Since these 2 numbers are consecutive odd numbers, the larger number should be 2 more than the smaller one (y+2).
Therefore, y + (y+2) = 284 2y +2 = 284 shift +2 to the other side and turn it into -2 2y = 284 - 2 2y = 282 shift x2 to the other side and turn it into /2 y = 282/2 y = 141
Now we got the smaller number, which is 141, we can also find the larger number by adding 2 to it. 141+2 = 143, Therefore, your answer is 141 and 143
We need to understand how to set up the equation to solve this. If they are consecutive odd integers, that means they're two odd numbers that are next to each other, like 3 and 5 or 27 and 29. There's always a two-integer difference between the two numbers since they're both odd, so we'll use that to set up our equation. Let's make the smaller integer x. That will make the larger integer x+2, since there is a difference between them of 2. That means our equation is x+x+2=284 or 2x+2=284. When we subtract 2 from each side and then divide by two, we'll get x=141, the first integer. That means the two integers are 141 and 143.
Subtraction: 18 - b Addition: 18 + b Multiplication: 18b, or 18 x b Division: 18 divided (My keyboard doesn't have a division sign?) by b Hope this helped.
