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stealth61 [152]
3 years ago
12

REALLY IMPORTANT!!! PLEASE HELP!!! If triangle ABC is a right triangle and BC is a semicircle, find the total area of the figure

below. what is the diameter of the semi-circle? _____ units. Area=____ units squared (rounded to the nearest hundredth. ) side AB is 3 units long. Side AC is 4 units long.
Mathematics
1 answer:
Artyom0805 [142]3 years ago
8 0

Answer:

The diameter of the semi-circle is 5 units

A = 9.82 units²

Step-by-step explanation:

In a circle the inscribed angle subtended by an arc of measure 180° (semi-circle) is a right angle

That means the angle whose vertex lies on a semi circle is a right angle

∵ Arc BC is a semi-circle

∵ Δ ABC is a right triangle

- That means BC is the diameter of the semi-circle and angle A

   is the right angle because A lies on the arc BC

∵ In Δ ABC

∵ m∠A = 90°

∵ AB = 3 units

∵ AC = 4 units

- Use Pythagoras theorem to find the length of BC

∵ (BC)² = (AB)² + (AC)²

∴ (BC)² = (3)² + (4)²

∴ (BC)² = 9 + 16

∴ (BC)² = 25

- Take √  for both sides

∴ BC = 5 units

∵ BC is the diameter of the semi-circle

∴ The diameter of the semi-circle is 5 units

∵ Area of the circle = πr²

- Multiply it by half to find the area of the semi-circle

∴ Area of semi-circle = \frac{1}{2} πr²

∵ The length of the radius is half the length of the diameter

   of the circle

∴ r = \frac{1}{2} (5) = 2.5 units

∴ A = \frac{1}{2} π (2.5)²

∴ A = 9.817477042

- Round it to the nearest hundredth

∴ A = 9.82 units²

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6 0
3 years ago
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Graph the system of linear inequalities

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Step 1: replace > symbol by = sign

x + y =5

step 2 : Solve the equation for y

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step 3: Now we make a table . plug in some number for x  and find out y

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Step 4:  we graph the table.

step 5: Shade the region that satisfies our inequality

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Follow the same steps to graph this inequality

After dividing the second equation  by -1 , we got the same as the first equation.

So we will get the same graph

Both graphs overlaps

The graph of first and second inequality overlaps

The graph is attached below

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