Answer:
35
Step-by-step explanation:
yeah becuse 35fttttt
Label your sides= hypotenuse(h),opposite(o),adjacent(a)
hypotenuse=longest(opposite the right angle)
opposite= opposite the other angle
adjacent= the other side
see which sides are involved
in this case it is adjacent and hypotenuse
so A and H
we have to use the SOHCAHTOA rule
Sin=o/h Cos=a/h Tan=o/a
we use cos because a and h are involved
Cos(15°)=62/x
rearrange the equation to find x
x= 62/cos(15)
put this in your calculator
x= 64.12
Notice the picture below
negative angles, are just angles that go "clockwise", namely, the same direction a clock hands move hmmm so.... and one revolution is just 2π
now, you can have angles bigger than 2π of course, by simply keep going around, so, if you go around 3 times on the circle, say "counter-clockwise", or from right-to-left, counter as a clock goes, 3 times or 3 revolutions will give you an angle of 6π, because 2π+2π+2π is 6π
now... say... you have this angle here... let us find another that lands on that same spot
by simply just add 2π to it :)

now, that's a positive one
and

to get more, just keep on subtracting or adding 2π
Answer:
(i) The length of AC is 32 units, (ii) The length of BC is 51 units.
Step-by-step explanation:
(i) Let suppose that AB and BC are collinear to each other, that is, that both segments are contained in the same line. Algebraically, it can be translated into this identity:

If we know that
and
, then:


The length of AC is 32 units.
(ii) Let suppose that AB and AC are collinear to each other, that is, that both segments are contained in the same line. Algebraically, it can be translated into this identity:


If we know that
and
, then:


The length of BC is 51 units.