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Degger [83]
3 years ago
9

HELPPPP PLEASEEEEEEEREEREEEE

Mathematics
1 answer:
Maksim231197 [3]3 years ago
7 0

Answer:

the correct answer is b :)))))!!!

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Vector A⃗ has magnitude 5.00 and is at an angle of 36.9∘ south of east. Vector B⃗ has magnitude 6.40 and is at an angle of 20.0∘
GrogVix [38]

Answer:

  (x, y) = (4, -3)

Step-by-step explanation:

Relative to straight east with angles measured CCW, the vector is ...

  5∠-36.9° = 5(cos(-36.9°), sin(-36.9°)) = 5(0.8, -0.6) = (4, -3)

4 0
3 years ago
Marty is asked to draw triangles with side lengths of 4 units and 2 units, and a non-included angle of 30°. Select all the trian
777dan777 [17]

Answer:

The drawn in the attached figure

see the explanation

Step-by-step explanation:

<em>First case</em>

In the triangle ABC

Let

a=4\ units\\b=2/ units\\B=30^o

Applying the law of sines

Find the measure of angle A

\frac{a}{sin(A)}=\frac{b}{sin(B)}

substitute the given values

\frac{4}{sin(A)}=\frac{2}{sin(30^o)}

sin(A)=1

so

A=90^o

Find the measure of angle C

In a right triangle

we know that

B+C=90^o ----> by complementary angles

B=30^o

therefore

C=60^o

Find the length side c

Applying the law of sines

\frac{c}{sin(C)}=\frac{b}{sin(B)}

substitute the given values

\frac{c}{sin(60^o)}=\frac{2}{sin(30^o)}

c=2\sqrt{3}\ units

therefore

The dimensions of the triangle are

A=90^o

B=30^o

C=60^o

a=4\ units\\b=2\ units\\c=2\sqrt{3}=3.46\ units

<em>Second case</em>

In the triangle ABC

Let

a=4\ units\\b=2/ units\\A=30^o

Applying the law of sines

Find the measure of angle B

\frac{a}{sin(A)}=\frac{b}{sin(B)}

substitute the given values

\frac{4}{sin(30^o)}=\frac{2}{sin(B)}

sin(B)=0.25

so

using a calculator

B=14.48^o

Find the measure of angle C

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

so

A+B+C=180^o

A=30^o\\B=14.48^o

therefore

30^o+14.48^o+C=180^o

C=135.52^o

Find the length side c

Applying the law of sines

\frac{c}{sin(C)}=\frac{a}{sin(A)}

substitute the given values

\frac{c}{sin(135.52^o)}=\frac{4}{sin(30^o)}

c=5.61\ units

therefore

The dimensions of the triangle are

A=30^o

B=14.48^o

C=135.52^o

a=4\ units\\b=2\ units\\c=5.61\ units

see the attached figure to better understand the problem

4 0
3 years ago
I need help with this I don't understand this
Mandarinka [93]

Answer:

45.8

Step-by-step explanation:

We need to find the surface area for this entire figure!

We can see that this is a pyramid here - we must find the area of the 3 triangles and the base triangle at the bottom.

The 3 triangles building up the pyramid are all equal to each other.

To find the area of a triangle, use  Area = base*height/2

Area=3(\frac{5*7}{3} )+(\frac{5*4.3}{2})\\Area=35+10.75=45.75

Round to the nearest tenth: 45.75 -> 45.8

4 0
3 years ago
I have to solve this system equation by graphing. by the way the equation is all in one,not separate​
victus00 [196]
This system equation is not solution
6 0
2 years ago
Algebraic factorisation simplification long question​
qwelly [4]

Answer:Algebra Questions, for Grade 10, on simplifying, factoring, evaluating expressions and solving equations are presented along with their answers

Step-by-step explanation:

I do not know if this helps or not but here you go!

3 0
2 years ago
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