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yan [13]
3 years ago
15

in a 4 kilometer race, a runner completes the first kilometer in 5.9 minutes, the second kilometer in 6.2 minutes, the third kil

ometer in 6.3 minutes, and the final kilometer in 6 minutes. the average speed of the runner for the race is approximately
Physics
2 answers:
ohaa [14]3 years ago
5 0
To find the average of data collected, add all of the measurements: 5.9+6.2+6.3+6= 12.2

Then, divide the total amount by the number of data collected which is 4: 12.2/4= 3.05

The average speed of the runner of the race is approximately 3.05 km/min

Feel free to ask me any other questions you might have :)
Kruka [31]3 years ago
5 0

Answer:

9.83 km/h

Explanation:

Given: in a 4 kilometer race, a runner completes the first kilometer in 5.9 minutes, the second kilometer in 6.2 minutes, the third kilometer in 6.3 minutes, and the final kilometer in 6 minutes.

To Find:  the average speed of the runner for the race.

Solution:

In a 4 kilometer race,

time required to travel first kilometer = 5.9 \text{minutes}

time required to travel seoond kilometer = 6.2 \text{minutes}

time required to travel third kilometer = 6.3 \text{minutes}

time required to travel final kilometer = 6 \text{minutes}

we know that,

\text{Average speed}=\frac{\text{Total distance traveled}}{\text{Total time taken}}

Total distance traveled = 4  \text{kilometer}

Total time taken = (5.9+6.2+6.3+6)

                           =  24.4 \text{minutes}

                           = \frac{24.4}{60}  \text{hours}

putting values,

\text{Average speed}=\frac{4}{\frac{24.4}{60}}

 \text{Average speed}=\frac{4\times60}{24.4}

                                            =9.83 \text{km}/ \text{h}

the average speed of the runner for the race is approximately 9.83 \text{km}/ \text{h}

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ss7ja [257]

Answer:

<h2>The answer is 5 s</h2>

Explanation:

The time taken can be found by using the formula

t =  \frac{d}{v}  \\

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v is the velocity

From the question we have

t =  \frac{20}{4}  \\

We have the final answer as

<h3>5 s</h3>

Hope this helps you

4 0
3 years ago
Read 2 more answers
A ball is thrown horizontally from the top of a building 14.9 m high. The ball strikes the ground at a point 107 m from the base
umka2103 [35]

Answer:

1) t=1.743 sec

2)Vo=61.388  m/sec

3)the x component of its velocity just be- fore it strikes the ground is the same as the  initial velocity of the ball that is=61.388  m/sec

4)Vf=17.08 m/s

Explanation:

1)From second equation of motion we get

h=Vit+(1/2)gt^2

here in case(a): Vi=0 m/s,h=14.9m,,put these values in above equation to find the time the ball is in motion

14.9=(0)*t+(1/2)(9.8)t^2

t^2=14.9/4.9

t^2=3.040 sec

t=1.743 sec

2) s=Vo*t

Putting values we get

107=Vo*1.743

Vo=61.388  m/sec

3)the x component of its velocity just be- fore it strikes the ground is the same as the  initial velocity of the ball that is=61.388  m/sec

4)From third equation of motion we know that

Vf^2-Vi^2=2gh

here Vi=0 m/s,h=14.9 m

Vf^2=Vi^2+2gh=0+2(9.8)(14.9)

Vf^2=292.04

Vf=17.08 m/s

8 0
4 years ago
Which statement is correct? Theories are accepted as true when a single experiment yields similar results to another one. When a
levacccp [35]
The third statement is correct.

3 0
3 years ago
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If 7 ounces of a sports drink contains 110 milligrams of sodium, what is the total number of milligrams of sodium in 20 ounces o
ehidna [41]

so you just take 110 divided by 7 and then you get the answer and times tthat by 20 and you get you answer which is 314.28 milligrams of sodium in 20 ounces of the sports drink.

7 0
3 years ago
Two electric charges, held a distance, dd, apart experience an electric force of magnitude, FF, between them. If one of the char
lorasvet [3.4K]

Answer:

F'=2F

Explanation:

The Coulomb's law states that the magnitude of the electrostatic force between two charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them:

F=\frac{kq_1q_2}{d^2}

In this case, we have q_1'=2q_1:

F'=\frac{kq'_1q_2}{d^2}\\F'=\frac{k(2q_1)q_2}{d^2}\\F'=2\frac{kq_1q_2}{d^2}\\F'=2F

3 0
3 years ago
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