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3 years ago

Can it is possible to complete half syllabus of physics class 11 in 8 days?

Physics

1 answer:

castortr0y [4]3 years ago

3 0

Answer:

In the human thoughts, there is possible and impossible. In God's world everything is possible. If you keep thinking this you'll never start to study. Just get up, open the book and start to study like you do. Believe in yourself!

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A speedboat travels from the dock to the first buoy, a distance of 20 meters, in 18 seconds. It began the trip at a speed of 0 m

LenaWriter [7]

So as a fact we do not know if the boat "burned tires" to reach the buoy :) the average velocity is +1,11 m/s. 20m divided by 18 seconds is +1.11 m/s

5 0

3 years ago

Read 2 more answers

Does an odometer measure distance or displacement

SashulF [63]

Odometer measures distance

3 0

4 years ago

Modeled after the two satellites problem (slide 12 in Lecture13, Universal gravity), imagine now if the period of the satellite

ikadub [295]

Answer:

R = 6.3456 10⁴ mile

Explanation:

For this exercise we will use Newton's second law where force is gravitational force

F = m a

The satellite is in a circular orbit therefore the acceleration is centripetal

a = v² / r

Where the distance is taken from the center of the Earth

G m M / r² = m v² / r

G M / r = v²

The speed module is constant, let's use the uniform motion relationships, with the length of the circle is

d = 2π r

v = d / t

The time for a full turn is called period (T)

Let's replace

G M / r = (2π r / T)²

r³ = G M T²²2 / 4π²

r = ∛ (G M T² / 4π²)

We have the magnitudes in several types of units

T = 88.59 h (3600 s / 1h) = 3.189 10⁵ s

Re = 6.37 10⁶ m

Let's calculate

r = ∛ (6.67 10⁻¹¹ 5.98 10²⁴ (3,189 10⁵)²/4π²)

r = ∛ (1.027487 10²⁴)

r = 1.0847 10⁸ m

This is the distance from the center of the Earth, the distance you want the surface is

R = r - Re

R = 108.47 10⁶ - 6.37 10⁶

R = 102.1 10⁶ m

Let's reduce to miles

R = 102.1 10⁶ m (1 mile / 1609 m)

R = 6.3456 10⁴ mile

6 0

3 years ago

The equivalent resistance of two resistors connected in series is always greater than the equivalent resistance of the same two

seraphim [82]

Answer:

True

Explanation:

Because the resistors in series is the sum of the two resistors given as

R= R1+R2

While that of resistors in parallel is the sum of the reciprocal of the resistance given as

1/R = 1/ R1+ 1/R2

So that of series connection will be greater

4 0

3 years ago

4. There are two categories of ultraviolet light. Ultraviolet A (UVA) has a wavelength ranging from 320 nm to 400 nm. It is not

vampirchik [111]

The ranges of frequency are:

UVA: $[7.50-9.38]\cdot 10^{14} Hz$

UVB: $[9.38-10.71]\cdot 10^{14} Hz$

Explanation:

The relationship between frequency and wavelength for an electromagnetic wave is the following:

$f = \frac{c}{\lambda}$

where

f is the frequency

$c=3.0\cdot 10^8 m/s$ is the speed of light

$\lambda$ is the wavelength

For the UVA, the range of wavelength is 320 nm - 400 nm, so

$\lambda_1 = 320 \cdot 10^{-9} m\\\lambda_2 = 400 \cdot 10^{-9} m$

So the corresponding frequencies are

$f_1 = \frac{3\cdot 10^8}{320\cdot 10^{-9}}=9.38\cdot 10^{14} Hz\\f_2= \frac{3\cdot 10^8}{400\cdot 10^{-9}}=7.50\cdot 10^{14} Hz$

For the UVB, the range of wavelength is 280 nm - 320 nm, so

$\lambda_1 = 280 \cdot 10^{-9} m\\\lambda_2 = 320 \cdot 10^{-9} m$

So the corresponding frequencies are

$f_1 = \frac{3\cdot 10^8}{280\cdot 10^{-9}}=1.07\cdot 10^{15} Hz\\f_2= \frac{3\cdot 10^8}{320\cdot 10^{-9}}=9.38\cdot 10^{14} Hz$

So the ranges of frequency are:

UVA: $[7.50-9.38]\cdot 10^{14} Hz$

UVB: $[9.38-10.71]\cdot 10^{14} Hz$

Learn more about waves, frequency and wavelength:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

3 0

3 years ago

Can it is possible to complete half syllabus of physics class 11 in 8 days?​

Can it is possible to complete half syllabus of physics class 11 in 8 days?