Answer:
Part of the question is missing but here is the equation for the function;
Consider the equation v = (1/3)zxt2. The dimensions of the variables v, x, and t are [L/T], [L], and [T] respectively.
Answer = The dimension for z = 1/T3 i.e 1/ T - raised to power 3
Explanation:
What is applied is the principle of dimensional homogenuity
From the equation V = (1/3)zxt2.
- V has a dimension of [L/T]
- t has a dimension of [T]
- from the equation, make z the subject of the relation
- z = v/xt2 where 1/3 is treated as a constant
- Substituting into the equation for z
- z = L/T / L x T2
- the dimension for z = 1/T3 i.e 1/ T - raised to power 3
Answer: hope it helps you...❤❤❤❤
Explanation: If your values have dimensions like time, length, temperature, etc, then if the dimensions are not the same then the values are not the same. So a “dimensionally wrong equation” is always false and cannot represent a correct physical relation.
No, not necessarily.
For instance, Newton’s 2nd law is F=p˙ , or the sum of the applied forces on a body is equal to its time rate of change of its momentum. This is dimensionally correct, and a correct physical relation. It’s fine.
But take a look at this (incorrect) equation for the force of gravity:
F=−G(m+M)Mm√|r|3r
It has all the nice properties you’d expect: It’s dimensionally correct (assuming the standard traditional value for G ), it’s attractive, it’s symmetric in the masses, it’s inverse-square, etc. But it doesn’t correspond to a real, physical force.
It’s a counter-example to the claim that a dimensionally correct equation is necessarily a correct physical relation.
A simpler counter example is 1=2 . It is stating the equality of two dimensionless numbers. It is trivially dimensionally correct. But it is false.
<h3>
Answer:</h3>
189.07 kPa
<h3>
Explanation:</h3>
Concept tested: Boyle's law
<u>We are given;</u>
- Initial volume of the syringe, V1 is 16 cm³
- Initial pressure of the syringe, P1 is 1.03 atm
- New volume of the syringe, V2 is 8.83 cm³
We are required to calculate the new pressure of the syringe;
- We are going to use the concept on Boyle's law of gases.
- According to the Boyle's law, for a fixed mass of a gas, the pressure is inversely proportional to its volume at constant temperature.
- At varying pressure and volume, k(constant) = PV and P1V1=P2V2
Therefore, to get the new pressure, P2, we rearrange the formula;
P2 = P1V1 ÷ V2
= ( 16 cm³ × 1.03 atm) ÷ 8.83 cm³
= 1.866 atm.
- Thus, the new pressure is 1.866 atm
- But, we need to convert pressure to Kpa
- Conversion factor is 101.325 kPa/atm
Thus;
Pressure = 1.866 atm × 101.325 kPa/atm
= 189.07 kPa
Hence, the new pressure of the air in the syringe is 189.07 kPa
Answer:
The length of an edge of each small cube is 3.43 nm.
Explanation:
Given that,
Temperature of ideal gas =27.0°C
Pressure = 1.00 atm
We need to calculate the length of an edge of each small cube
Using gas equation
For, N = 1
Where,
N = number of molecule
k = Boltzmann constant
T = temperature
P= pressure
Put the value into the formula
Now, for the cube
Hence, The length of an edge of each small cube is 3.43 nm.
A proton repelling another proton
Like charges of the protons would repel one another.
