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Anna007 [38]
2 years ago
9

Metal workers and theory causes of accident​

Physics
1 answer:
ser-zykov [4K]2 years ago
4 0

The Domino principle Heinrich supplied a fixed of theorems referred to as 'the axioms of industrial protection'. is the theory causes of the accident.

The primary axiom treated coincidence causation, declaring that 'the prevalence of damage continuously results from a complex sequence of things, the final one among which being the twist of fate itself.

In keeping with the natural hazard theory, everyone in any given set of workers has the same danger of being concerned about a coincidence. It similarly means that there's no unmarried discernible sample of occasions that results in a coincidence

Main factors to an accident.

  • Ancestry & social environment.
  • The fault of the person.
  • unsafe act/mechanical or bodily chance.
  • accident.
  • damage.

Learn more about accidents​ here:-brainly.com/question/8430576

#SPJ9

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Consider the equation . The dimensions of the variables v, x, and t are , , and , respectively. The numerical factor 3 is dimens
Vinvika [58]

Answer:

Part of the question is missing but here is the equation for the function;

Consider the equation v = (1/3)zxt2. The dimensions of the variables v, x, and t are [L/T], [L], and [T] respectively.

Answer = The dimension for z = 1/T3 i.e 1/ T - raised to power 3

Explanation:

What is applied is the principle of dimensional homogenuity

From the equation V = (1/3)zxt2.

  • V has  a dimension of [L/T]
  • x has a dimension of [L]
  • t has a dimension of [T]
  • from the equation, make z the subject of the relation
  • z = v/xt2 where 1/3 is treated as a constant
  • Substituting into the equation for z
  • z = L/T / L x T2
  • the dimension for z = 1/T3 i.e 1/ T - raised to power 3
5 0
3 years ago
is dimensionally correct relation necessarily to be a correct physical relation? explain with example.​
Andreas93 [3]

Answer: hope it helps you...❤❤❤❤

Explanation: If your values have dimensions like time, length, temperature, etc, then if the dimensions are not the same then the values are not the same. So a “dimensionally wrong equation” is always false and cannot represent a correct physical relation.

No, not necessarily.

For instance, Newton’s 2nd law is  F=p˙ , or the sum of the applied forces on a body is equal to its time rate of change of its momentum. This is dimensionally correct, and a correct physical relation. It’s fine.

But take a look at this (incorrect) equation for the force of gravity:

F=−G(m+M)Mm√|r|3r  

It has all the nice properties you’d expect: It’s dimensionally correct (assuming the standard traditional value for  G ), it’s attractive, it’s symmetric in the masses, it’s inverse-square, etc. But it doesn’t correspond to a real, physical force.

It’s a counter-example to the claim that a dimensionally correct equation is necessarily a correct physical relation.

A simpler counter example is  1=2 . It is stating the equality of two dimensionless numbers. It is trivially dimensionally correct. But it is false.

4 0
3 years ago
A syringe of volume 16 cm3 is filled with air to a pressure of 1.03 atm. If the piston of the syringe is pushed to change the vo
denpristay [2]
<h3>Answer:</h3>

189.07 kPa

<h3>Explanation:</h3>

Concept tested: Boyle's law

<u>We are given;</u>

  • Initial volume of the syringe, V1 is 16 cm³
  • Initial pressure of the syringe, P1 is 1.03 atm
  • New volume of the syringe, V2 is 8.83 cm³

We are required to calculate the new pressure of the syringe;

  • We are going to use the concept on Boyle's law of gases.
  • According to the Boyle's law, for a fixed mass of a gas, the pressure is inversely proportional to its volume at constant temperature.
  • That is; P α 1/V
  • At varying pressure and volume, k(constant)  = PV and P1V1=P2V2

Therefore, to get the new pressure, P2, we rearrange the formula;

P2 = P1V1 ÷ V2

     = ( 16 cm³ × 1.03 atm) ÷ 8.83 cm³

    = 1.866 atm.

  • Thus, the new pressure is 1.866 atm
  • But, we need to convert pressure to Kpa
  • Conversion factor is 101.325 kPa/atm

Thus;

Pressure = 1.866 atm × 101.325 kPa/atm

               = 189.07 kPa

Hence, the new pressure of the air in the syringe is 189.07 kPa

3 0
3 years ago
Consider an ideal gas at 27.0 degrees Celsius and 1.00 atmosphere pressure. Imagine the molecules to be uniformly spaced, with e
antiseptic1488 [7]

Answer:

The length of an edge of each small cube  is 3.43 nm.

Explanation:

Given that,

Temperature of ideal gas =27.0°C

Pressure = 1.00 atm

We need to calculate the length of an edge of each small cube

Using gas equation

PV=nRT

PV=NkT

V=\dfrac{NkT}{P}

For, N = 1

Where,

N = number of molecule

k = Boltzmann constant

T = temperature

P= pressure

Put the value into the formula

V=\dfrac{1\times1.38\times10^{-23}\times(27+273)}{1.03\times10^{5}}

V=4.019\times10^{-26}\ m^3

Now, for the cube

V=L^3

L=V^{\frac{1}{3}}

L=(4.019\times10^{-26})^{\frac{1}{3}}

L=3.43\times10^{-9}\ m

L=3.43 nm

Hence, The length of an edge of each small cube  is 3.43 nm.

3 0
3 years ago
Which of the following is an example of the electrostatic force acting in an atom?
777dan777 [17]
A proton repelling another proton

Like charges of the protons would repel one another.
7 0
3 years ago
Read 2 more answers
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