First the amount of work done in lifting up the snow ball to a height of 1.2m is equal to the potential energy of the ball after the lift.
Therefore mass× gravitational pull×height will give us the work done
=3.2kg ×9.8N/kg×1.2m
=37.632J
then, the work done over the 25m distance if found by the following formula: work done=force×distance
=1.0N×25m
=25J
On reaching the headless snowman you have to lift the ball a further 1.1m to place it as the head 2.3m high.
therefore this will be a change in potential energy which is equal to work done in lifting the ball the additional 1.1m
=m×g×h
=3.2kg×9.8N/kg×1.1m
=34.496J
To get the total we add the amount of work done in the various instances.
Answer:
The star is at a distance of 100 parsecs.
Explanation:
The distance can be determined by means of the distance modulus:
(1)
Where M is the absolute magnitude, m is the apparent magnitude and d is the distance in units of parsec.
Therefore, d can be isolated from equation 1

Then, Applying logarithmic properties it is gotten:
(2)
The absolute magnitude is the intrinsic brightness of a star, while the apparent magnitude is the apparent brightness that a star will appear to have as is seen from the Earth.
Since both have the same spectral type is absolute magnitude will be the same.
Finally, equation 2 can be used:
Hence, the star is at a distance of 100 parsecs.
Key term:
Parsec: Parallax of arc seconds
Answer:
makes a transition from a high to a lower energy state
Explanation:
The emission spectrum is the spectrum of electromagnetic radiation emitted due to the transition from a state of high energy to a state of lower energy made by an electron in the atoms of the chemical element or compound. The emitted photons have an energy equal to the difference in energy between the two states.
Answer:
Total heat transfer is positive
Total work transfer is positive
Explanation:
The first law of thermodynamics states that when a system interacts with its surrounding, the amount of energy gained by the system must be equal to the amount of energy lost by the surrounding. In a closed system, exchange of energy with the surrounding can be done through heat and work transfer.
Heat transfer to a system is positive and that transferred from the system is negative.
Also, work done by a system is positive while the work done on the system is negative.
Therefore, from the question, since the heat engine inputs 10kJ of heat, then heat is being transferred to the system. Hence, the sign of the total heat transfer is positive (+ve)
Also, since the heat engine outputs 5kJ of work, it implies that work is being done by the system. Hence the sign of the total work transfer is also positive (+ve).
Answer:
potential energy which later on gets converted to kinetic energy of an object