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makvit [3.9K]
3 years ago
15

So whats the answer.

Mathematics
1 answer:
Neko [114]3 years ago
5 0

Answer:

69

Step-by-step explanation:

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A simple random sample of size nequals40 is drawn from a population. The sample mean is found to be 103.9​, and the sample stand
yan [13]

Answer:

There is enough evidence to support the claim that the population mean is greater than 100

Step-by-step explanation:

<u>Step 1</u>: We state the hypothesis and identify the claim

H_0:\mu=100 and H_1:\mu \:>\:100 (claim)

<u>Step 2</u>: Calculate the test value.

t=\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }

\implies t=\frac{103.9-100}{\frac{21.9}{\sqrt{40} } }=1.1263

<u>Step 3</u>: Find the P-value. The p-value obtained from a calculator is using d.f=39 and test-value 1.126 is 0.134

<u>Step 4</u>: We fail to reject the null hypothesis since P-value  is greater that the alpha level. (0.134>0.05).

<u>Step 5</u>: There is enough evidence to support the claim that the population mean is greater than 100.

<u>Alternatively</u>: We could also calculate the critical value to obtain +1.685 for \alpha=0.05 and d.f=39 and compare to the test-value:

The critical value (1.685>1.126) falls in the non-rejection region. See attachment.

NB: The t- distribution must be used because the population standard deviation is not known.

5 0
4 years ago
PLEASE HELP I WILL GIVE BRAINLIEST!!!!!!
Luden [163]

Answer:

C. 114

Step-by-step explanation:

bikes have 2 wheels

skateboards have 4 wheels

incline skates have 8 wheels in total

7*2 = 14

9*4 = 36

8*8 = 64

if you add all of these up you get 114 wheels in total. 8*8 was from 24-7-9 = 8

8 0
3 years ago
in your class 7 students do not receive weekly allowance, 5 students receive $3, 7 students receive $5, 3 students receive $6, a
Gemiola [76]
The mean is the average of a set of numbers.
To find the mean of this data, form a number set by gathering all the numbers.
We need to find the average weekly allowance. To do this, each number in the number set should be the different allowances, and their quantity is the number of students who earned that allowance.
In this case, there would be seven 0s, five 3s, seven 5s, three 6s, and two 8s.

The numbers are:
0, 0, 0, 0, 0, 0, 0, 3, 3, 3, 3, 3, 5, 5, 5, 5, 5, 5, 5, 6, 6, 6, 8, 8

To find the mean of these numbers, add then together then divide by the total amount of numbers.

This means doing:
(0 + 0 + 0 + 0 + 0 + 0 + 0 + 3 + 3 + 3 + 3 + 3 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 6 + 6 + 6 + 8 + 8) / 7 + 5 + 7 + 3 + 2

An easier formula could be used by using multiplication.
This would be [7(0) + 5(3) + 7(5) + 3(6) + 2(8)] / 24
This is a lot easier to read!
Now to solve it.
7 • 0 = 0
5 • 3 = 15
7 • 5 = 35
3 • 6 = 18
2 • 8 = 16
0 + 15 + 35 + 18 + 16 = 84
84 / 24 = 3.5

The mean is 3.5, or $3.50
This means that the average weekly allowance amongst these students is $3.50.

Hope this helps!
4 0
3 years ago
In Illinois, 9% of all drivers arrested for DUI (Driving Under the Influence) are repeat offenders; that is, they have been arre
Veseljchak [2.6K]

Answer:

a) 21.58% probability that exactly 3 people are repeat offenders

b) 97.91% probability that at least one person is a repeat offender

c) 3.69

d) 1.83

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

9% of all drivers arrested for DUI (Driving Under the Influence) are repeat offenders

This means that p = 0.09

41 people arrested for DUI in Illinois are selected at random.

This means that n = 41

a. What is the probability that exactly 3 people are repeat offenders?

This is P(X = 3).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{41,3}.(0.09)^{3}.(0.91)^{38} = 0.2158

21.58% probability that exactly 3 people are repeat offenders

b. What is the probability that at least one person is a repeat offender?

Either none are repeat offenders, or at least one is. The sum of the probabilities of these outcomes is 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1).

Then

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = 0) = C_{41,0}.(0.09)^{0}.(0.91)^{41} = 0.0209

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0209 = 0.9791

97.91% probability that at least one person is a repeat offender

c. What is the mean number of repeat offenders?

E(X) = np = 41*0.09 = 3.69

d. What is the standard deviation of the number of repeat offenders?

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{41*0.09*0.91} = 1.83

4 0
3 years ago
What is the slop of the line y = 3
Otrada [13]

3/1 is the slope of the line

5 0
3 years ago
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