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klio [65]
3 years ago
7

PLEASE HELP ME!! due soon

Mathematics
2 answers:
leonid [27]3 years ago
6 0

Answer:

4

Step-by-step explanation:

lisabon 2012 [21]3 years ago
3 0
Re post the picture
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Could someone please help me with this one
Dvinal [7]
The answer is a because when they are added that's what they equal then divide by 5
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3 years ago
Which type of transformation must have occurred in order to map triangle RST to its image, triangle R'S'T?​
harkovskaia [24]

Answer:

Reflection over the y axis

Step-by-step explanation:

You can picture this graph on a piece of paper.  If you fold the paper over the y axis/ the line in the middle, T would map onto T', S onto S' and R onto R'.  This is a reflection

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Nonamiya [84]

Answer:

1.>

2.>

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Step-by-step explanation:

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3 years ago
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Please help ASAP! THANKS<br>WILL MARK BRAINLIEST
lara31 [8.8K]

Answer:

square root of 1

Step-by-step explanation:

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8 0
3 years ago
An Archer shoots an arrow horizontally at 250 feet per second. The bullseye on the target and the arrow are initially at the sam
Genrish500 [490]

Answer:

<h2>1.84feet</h2>

Step-by-step explanation:

Using the formula for finding range in projectile, Since range is the distance covered in the horizontal direction;

Range R = U\sqrt{\frac{H}{g} }

U is the velocity of the arrow

H is the maximum height reached = distance below the bullseye reached by the arrow.

R is the horizontal distance covered i.e the distance of the target from the archer.

g is the acceleration due to gravity.

Given R = 60ft, U = 250ft/s, g = 32ft/s H = ?

On substitution,

60 = 250\sqrt{\frac{H}{32}} \\\frac{60}{250} = \sqrt{\frac{H}{32}}\\\frac{6}{25} = \sqrt{\frac{H}{32}

Squaring both sides we have;

(\frac{6}{25} )^{2} = (\sqrt{\frac{H}{32} } )^{2} \\\frac{36}{625} =  \frac{H}{32} \\625H = 36*32\\H = \frac{36*32}{625} \\H = 1.84feet

The arrow will hit the target 1.84feet below the bullseye.

5 0
3 years ago
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