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rjkz [21]
3 years ago
7

NEED MAJOR HELP WITH HW!!! ps: will mark brainliest :)

align="absmiddle" class="latex-formula">
1: 1/2 of 3/5=
2: 3/4 of 5/7=
Multiply. Express each product in simplest form:
3: 5/6 of 9/11
4: 7/10 of 5/9
5: 7/8 × 10/14
6: 8/9 × 9/10
7: 3/5 × 4/12
8: 5/7 × 7/10
Solve show your work
9: Tian has 56 paper. He gives 3/4 of them to Joe. Joe gives 2/7 of what he receives to Rahul. How many paper clips did Rahul get?
10: Tony is given 9/10 hour to mow a lawn. He only uses 2/3 of the given time to mow the lawn. How much time is left?
11: Keith spends 1/6 of his savings on a magazine and 2/5 of the remainder on a storybook. What fraction of his savings is left?
12: There are some caps in a box. 1/6 of them are red, 1/3 are blue, and 3/7 of the remainder is green. If there are 27 green caps, how many caps are there altogether?
Mathematics
1 answer:
TiliK225 [7]3 years ago
6 0
1.5
2.5
45/66
35/90
70/120
81/90
12/45
35/70
rahul got 4
15minutes
4/15
43
  I did this in class today i have the worksheet with answers Your welcome no work needed put that on the paper

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Need help please thank you
marshall27 [118]
which one, and um this catagory is english
5 0
3 years ago
Read 2 more answers
What are the zeros of f(x)=x(x-8)
Flura [38]

Answer:

The zeros are x=0,x=8

Step-by-step explanation:

f(x)=x(x-8)

To find the zeros, we set the equation equal to zero

0 = x(x-8)

Using the zero product property

x= 0  x-8=0

x=0  x=8

The zeros are 0,8

8 0
3 years ago
Read 2 more answers
Answer correctly for the brainliest answer
Dahasolnce [82]

Similar triangles so AC:BC=AE:DE

15+6=21 = AE

15:12.5=21:?

to get from 15 to 12.5 you divide by 15 and times by 12.5 so do this the to the other side

21/15=1.4

1.4 x 12.5=17.5

So DE=17.5

4 0
2 years ago
A dresser contains six pairs of shorts one each in the colors, red, black, blue, green, khaki, and gray. The dresser also contai
marissa [1.9K]
Answer: 1/24

---------------------------------------------------------------------
---------------------------------------------------------------------

Work Shown:

A = selects green pair of shorts
B = selects gray t-shirt

P(A) = probability of selecting green shorts
P(A) = (number of green shorts)/(number of shorts total)
P(A) = 1/6
P(B) = probability of selecting gray t-shirt
P(B) = (number of gray t-shirts)/(number of t-shirts total)
P(B) = 1/4

P(A and B) = probability of selecting green shorts AND gray t-shirt
P(A and B) = P(A)*P(B) ... since A and B are independent events
P(A and B) = (1/6)*(1/4)
P(A and B) = (1*1)/(6*4)
P(A and B) = 1/24

Note: The fraction 1/24 is approximately equal to 0.041667

5 0
3 years ago
Rectangle ABCD has vertices at (-7,-2); (1, -2); (1, -8); and (-7, -8) respectively. If GHJK is a similar rectangle where G(2, 5
Gennadij [26K]

Answer:

Points J and K could be located at:

J(2,2)

K(6,2)

Step-by-step explanation:

Consider the vertices have a x and y coordinate:

A: x coordinate=-7  y coordinate=-2

B: x coordinate=1  y coordinate=-2

C: x coordinate=1  y coordinate=-8

D: x coordinate=-7  y coordinate=-8

G: x coordinate=2  y coordinate=5

H: x coordinate=6  y coordinate=5

Then it is possible to calculate the distance between the x and y coordinates:

x coordinate of Vertices AB:

x coordinate of B- x coordinate of A=1-(-7)=8

The distance between A and B is 8

y coordinate of Vertices AC:

y coordinate of A- y coordinate of C=-2-(-8)=6

The distance between A and C is 6

Then we know that the side AB of Rectangle ABCD measures 8 and the side AC, measures 6.

Repeat the analysis  with Rectangle GHJK. In this case, is only possible to calculate the distance with x coordinate.

x coordinate of Vertices GH:

x coordinate of H- x coordinate of G=6-(2)=4

The distance between G and H is 4

We can see that the distance in x of the Rectangle ABCD is 8, and the distance in x of the Rectangle GHJK is 4, it means that <em>the measure of ABCD is twice GHJK.</em>

Then, if the distance in y coordinate of Vertices AC is 6, we could say that the distance in<em> y coordinate of Vertices GJ is 3.</em>

<em />

Points J and K could be located at:

J(2,2)

K(6,2)

3 0
3 years ago
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