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Harlamova29_29 [7]
3 years ago
14

Percy pulls on a rope that is held up by a pulley, like the one shown. The pulley is near the ceiling, and the other end of the

rope is attached to a crate. Percy applies 75 N of force to the rope, and the rope lifts the crate by applying a force of 75 N. What is the mechanical advantage of the machine?
Physics
2 answers:
Anton [14]3 years ago
6 0
The Mechanical Advantage would be 
1

75÷75= 1
Leviafan [203]3 years ago
5 0

Answer:

B

Explanation:

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the orion nebula (at least the part we can see) is not very old (yet). while several hot, massive stars have had a chance to for
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One of the brightest nebulae in the night sky, the Orion Nebula may be seen with the unaided eye. The Trapezium is a young open cluster of four main stars in this magnitude 4 interstellar cloud of ionized atomic hydrogen.

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1 year ago
How can people reach their full potential?
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6 0
4 years ago
A wad of clay of mass m1 = 0.49 kg with an initial horizontal velocity v1 = 1.89 m/s hits and adheres to the massless rigid bar
notka56 [123]

Answer:

<h2>The angular velocity just after collision is given as</h2><h2>\omega = 0.23 rad/s</h2><h2>At the time of collision the hinge point will exert net external force on it so linear momentum is not conserved</h2>

Explanation:

As per given figure we know that there is no external torque about hinge point on the system of given mass

So here we will have

L_i = L_f

now we can say

m_1v_1\frac{L}{2} = (m_2L^2 + m_1(\frac{L}{2})^2)\omega

so we will have

0.49(1.89)(0.45) = (2.13(0.90)^2 + 0.49(0.45)^2)\omega

\omega = 0.23 rad/s

Linear momentum of the system is not conserved because at the time of collision the hinge point will exert net external force on the system of mass

So we can use angular momentum conservation about the hinge point

6 0
3 years ago
Non examples of gravity ?
Afina-wow [57]
Floating. When you have no gravity you have nothing to be pushing you down to the floor so that would be an example of no gravity pushing on you.
3 0
3 years ago
Read 2 more answers
in a softball game, a batter hits the ball at the velocity of 27m/s and angle of 40 shown below. What is the maximum range of th
Nata [24]

Answer:

R = 73.25 m

Explanation:

We have,

Initial speed of the ball is 27 m/s

It is projected at an angle of 40 degrees

The maximum range of the ball is given by :

R=\dfrac{u^2\sin2\theta}{g}

Plugging all the values we get :

R=\dfrac{(27)^2\sin2(40)}{9.8}\\R=73.25\ m

So, the maximum range of the ball is 73.25 m

8 0
3 years ago
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