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omeli [17]
3 years ago
5

35 points!! How much does a fish weigh if its tail weighs 4 kilograms, it's head weighs as much as it's tail and half its body,

and half its body weighs as much as it's head and tail together?
Mathematics
1 answer:
NeX [460]3 years ago
4 0

Let t, h, b represent the weighs of tail, head, and body, respectively.

t = 4 . . . . given

h = t + b/2 . . . . the head weighs as much as the tail and half the body

b/2 = h + t . . . . half the body weighs as much as the head and tail

_____

Substituting for b/2 in the second equation using the expression in the third equation, we have

... h = t + (h + t)

Subtracting h from both sides gives

... 0 = 2t . . . . . . in contradiction to the initial statement about tail weight.

Conclusion: there's no solution to the problem given here.

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Arranging of books is an illustration of permutation and combination

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The number of books is given as:

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Read more about permutation and combination at:

brainly.com/question/1216161

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3 years ago
Find the difference (20m+3)-(7m-5)
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Answer:

Simplifying

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Remove parenthesis around (3 + 20m)

3 + 20m + -1(7m + -5) = 0

Reorder the terms:

3 + 20m + -1(-5 + 7m) = 0

3 + 20m + (-5 * -1 + 7m * -1) = 0

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Reorder the terms:

3 + 5 + 20m + -7m = 0

Combine like terms: 3 + 5 = 8

8 + 20m + -7m = 0

Combine like terms: 20m + -7m = 13m

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Solving

8 + 13m = 0

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-8' to each side of the equation.

8 + -8 + 13m = 0 + -8

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Simplifying

m = -0.6153846154Step-by-step explanation:

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