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konstantin123 [22]
3 years ago
15

What is the relationship between 8.76×10^6 and 8.76×10^2

Mathematics
2 answers:
aleksley [76]3 years ago
7 0

Answer:

\frac{8.76*10^{6}}{8.76*10^{2}}=\frac{1000000}{100}=10000

dusya [7]3 years ago
6 0
<span>Number 8.76×10^6 is </span>10,000 times greater than <span>8.76×10^2</span>
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A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and
mr Goodwill [35]

Answer:

Bias for the estimator = -0.56

Mean Square Error for the estimator = 6.6311

Step-by-step explanation:

Given - A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and X2. The mean is estimated using the formula (3X1 + 4X2)/8.

To find - Determine the bias and the mean squared error for this estimator of the mean.

Proof -

Let us denote

X be a random variable such that X ~ N(mean = 4.5, SD = 7.6)

Now,

An estimate of mean, μ is suggested as

\mu = \frac{3X_{1} + 4X_{2}  }{8}

Now

Bias for the estimator = E(μ bar) - μ

                                    = E( \frac{3X_{1} + 4X_{2}  }{8}) - 4.5

                                    = \frac{3E(X_{1}) + 4E(X_{2})}{8} - 4.5

                                    = \frac{3(4.5) + 4(4.5)}{8} - 4.5

                                    = \frac{13.5 + 18}{8} - 4.5

                                    = \frac{31.5}{8} - 4.5

                                    = 3.9375 - 4.5

                                    = - 0.5625 ≈ -0.56

∴ we get

Bias for the estimator = -0.56

Now,

Mean Square Error for the estimator = E[(μ bar - μ)²]

                                                             = Var(μ bar) + [Bias(μ bar, μ)]²

                                                             = Var( \frac{3X_{1} + 4X_{2}  }{8}) + 0.3136

                                                             = \frac{1}{64} Var( {3X_{1} + 4X_{2}  }) + 0.3136

                                                             = \frac{1}{64} ( [{3Var(X_{1}) + 4Var(X_{2})]  }) + 0.3136

                                                             = \frac{1}{64} [{3(57.76) + 4(57.76)}]  } + 0.3136

                                                             = \frac{1}{64} [7(57.76)}]  } + 0.3136

                                                             = \frac{1}{64} [404.32]  } + 0.3136

                                                             = 6.3175 + 0.3136

                                                              = 6.6311

∴ we get

Mean Square Error for the estimator = 6.6311

6 0
3 years ago
What is 3p + 2 &gt; -10
bezimeni [28]

Answer:

p> -4

Step-by-step explanation:

3p + 2 > -10

3p > -10 -2

p> -4

7 0
2 years ago
Write two numbers that multiply to the value on top and add to the value on bottom.
Marizza181 [45]

Answer:

2?

Step-by-step explanation:

6 0
3 years ago
a movie theater is located at a, b to get from your house to the movie theater, you walk 4 blocks east and then 5 blocks north.
melomori [17]

    N

W       E   X-axis

     S

  Y-axis

<h2>(4,5)</h2>

 x,y

7 0
2 years ago
The sum of two consecutive integers is 329
saw5 [17]
A = first integer
a + 1 = 2nd integer

a + a + 1 = 329
2a + 1 = 329
2a = 329 - 1
2a = 328
a = 164

a + 1 = 164 + 1 = 165

so ur 2 consecutive integers are : 164 and 165
3 0
3 years ago
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