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NNADVOKAT [17]
3 years ago
13

A coin is tossed 12 times. What is the probability of getting heads exactly 7 times?

Mathematics
2 answers:
nlexa [21]3 years ago
7 0
17% chance I think.
olchik [2.2K]3 years ago
4 0

Answer:

Once the number of possible heads and tail in 12 tosses is 2^{12} =4096

\frac{12!}{\left(7!\right)\left(5!\right)}\\\\\frac{12\cdot \:11\cdot \:10\cdot \:9\cdot \:8}{5!}\\\\\frac{95040}{120}\\\\792

So the probability of getting exactly  8  heads in  12  coin tosses is: \frac{792}{4096}

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Need HELP PLS PIC ATTACHED
Vera_Pavlovna [14]

Answer:

4x^{2}-13x+10

Step-by-step explanation:

(4x+5)(x-2)

Multiply each term in the first parenthesis by each term in the second (foil)

Step 1: Expand it by writing out each multiplication. I added a picture showing which order to do it. (go in order of green, red, blue, yellow.) (you can remember this as first, outside, inside, last.)

When you expand it'll look like: 4x⋅x+4x⋅-2-5x-5⋅-2

Step 2: Calculate product

4x⋅x+4x⋅-2-5x-5⋅-2 (for the 4x⋅x it would be written like 4x^{2})

   4x^{2}+4x⋅-2-5x-5⋅-2

4x^{2}+4x⋅-2-5x-5⋅-2 (4x⋅-2 becomes -8x) (multiply 4x times -2)

4x^{2}-8x-5x-5⋅-2

4x^{2}-8x-5x-5⋅-2 (-5⋅-2 becomes +10) (multiply -5 times -2)

4x^{2}-8x-5x+10

Step 3: collect like terms

4x^{2}-8x-5x+10 (-8x-5x becomes -13x) (-8x times -5x)

4x^{2}-13x+10 is the most simplified so it should be your final answer

4 0
1 year ago
The product of two consecutive even integers is 360360. find the integers.
professor190 [17]
There are no 2 consecutive integers which give a product 360360
5 0
3 years ago
Need help asappp
lozanna [386]

Answer:

552

Step-by-step explanation:

4 0
3 years ago
Find the sumofthe geometrical progression of five terms, of which the first term is 7 and the multiplier is 7.Verify that the su
777dan777 [17]

Answer:

The sum of first five term of GP is 19607.

Step-by-step explanation:

We are given the following in the question:

A geometric progression with 7 as the first term and 7 as the common ration.

a, ar, ar^2,...\\a  = 7\\r = 7

7, 7^2, 7^3, 7^4...

Sum of n terms in a geometric progression:

S_n = \displaystyle\frac{a(r^n - 1)}{(r-1)}

For sum of five terms, we put n= 5, a = 7, r = 7

S_5 = \displaystyle\frac{7(7^5 - 1)}{(7-1)}\\\\S_5 = 19607

The sum of first five term of GP is 19607.

Verification:

2801\times 7 = 19607

Thus, the sum is equal to product of 2801 and 7.

7 0
3 years ago
Circle groups to show 4x(2x2).
MrRa [10]
The answer is 16 ok its going to help mabye
6 0
3 years ago
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