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NNADVOKAT [17]
3 years ago
13

A coin is tossed 12 times. What is the probability of getting heads exactly 7 times?

Mathematics
2 answers:
nlexa [21]3 years ago
7 0
17% chance I think.
olchik [2.2K]3 years ago
4 0

Answer:

Once the number of possible heads and tail in 12 tosses is 2^{12} =4096

\frac{12!}{\left(7!\right)\left(5!\right)}\\\\\frac{12\cdot \:11\cdot \:10\cdot \:9\cdot \:8}{5!}\\\\\frac{95040}{120}\\\\792

So the probability of getting exactly  8  heads in  12  coin tosses is: \frac{792}{4096}

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Answer:

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I assume that the answer is "r"

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2 years ago
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Number 18 pls help me
Harman [31]
Lila did it correctly. The answer is 324

Following PEMDAS, we first focus on the parenthesis. So we simplify 9-3 to get 6

So we go from 
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The next step is applying exponents. In this case, squaring the terms, so we go from
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Next is multiplying
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Finally, add up 288 and 36 to get 288+36 = 324

That confirms that Lila is correct

----------------------

The error that Rob made is that he computed 18*4^2+9^2-3^2 but it is NOT correct. Saying (x-y)^2 = x^2-y^2 isn't a true equation for all x and y. Again you have to simplify what is in the parenthesis first, and then you can square it. Or you must use the FOIL rule to expand out (9-3)^2


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1/2
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