The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
<h3>What is the radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.?</h3>
Generally, the equation for side lengths AB is mathematically given as
Triangle ABC has side lengths
Where
- AB = 65,
- BC = 33,
- AC = 56.
Hence
r √ 2 · (89 √ 2/2 − r √ 2) = r(89 − 2r),
r = 89 − 65
r= 24.
In conclusion, The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
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The answer is a! i hope this helps you!
Janna behanihe invented it
Answer:
For the second one: NO congruent to MO.
For the third one: angle N congruent to angle O.
:)
Answer:
160
Step-by-step explanation:
Plug in 6 for r, and 8 for s in the expression:
(r)(s) + (14)(s) = (6)(8) + (14)(8)
Remember to follow PEMDAS. First, multiply, then add:
(6 * 8) + (14 * 8)
48 + 112
112 + 48 = 160
160 is your answer.
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