All categories

3 years ago

What’s the awnser for this question I do not understand

Mathematics

2 answers:

ella [17]3 years ago

6 0

Answer:

the total surface area is 40 + 12 + 15 = 67 square units

Step-by-step explanation:

Refer to the diagram:

the combined area of the top and bottom is 2(5·4) = 40:

the combined area of the ends is 2(1.5·4) = 12; and

the combined area of the front and back is 2( 5 · 1.5) = 15

and so the total surface area is 40 + 12 + 15 = 67 square units

Vesna [10]3 years ago

6 0

Answer:

The answer is 67 units^2

Step-by-step explanation:

The formula: (LW+WH+LH)*2

Plug in the numbers: (20+6+7.5)*2

Combine like terms: (33.5)*2

Multiply: 33.5*2= 67 units^2

You might be interested in

Approximate the area between the xxx-axis and h(x) = \dfrac{1}{7-x}h(x)= 7−x 1 h, (, x, ), equals, start fraction, 1, divided

tiny-mole [99]

Answer:

$\dfrac{47}{60}$ sq. units.

Step-by-step explanation:

The given function is

$h(x)=\dfrac{1}{7-x}$

We need to find the area between x-axis and the given function from x=2 to x=5.

Left Riemann sum formula of area:

$Area=\sum_{n=0}^{N-1}f(x_n)(\Delta x_n)$

For given question,

$Area=\sum_{n=2}^{5-1}f(x_n)(\Delta x_n)$

$Area=\sum_{n=2}^{4}f(x_n)(\Delta x_n)$

$Area=f(x_2)(3-2)+f(x_3)(4-3)+f(x_4)(5-4)$

Now,

$Area=\dfrac{1}{7-2}\times (1)+\dfrac{1}{7-3}\times (1)+\dfrac{1}{7-4}\times (1)$

$Area=\dfrac{1}{5}+\dfrac{1}{4}+\dfrac{1}{3}$

$Area=\dfrac{12+15+20}{60}$

$Area=\dfrac{47}{60}$

Therefore, the required area is $\dfrac{47}{60}$ sq. units.

5 0

3 years ago

I just two questions :)

pogonyaev

Answer:

Hi There!!

Step-by-step explanation:

Your answers are:

I hope this helps!!

- abakugosimp

7 0

3 years ago

Read 2 more answers

Help me please? c: I only have 4 questions left and I'm a bit stuck

prohojiy [21]

1.168 rounded off to nearest thousands = 1168

6 0

3 years ago

Plz help. pl and thank u

Verizon [17]

Answer: sorry i cant read it its to small

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers

PLEASE HELP ME OUT!!

andrey2020 [161]

Short answer A
This one is exactly the same (with number changes) as the last one. You cannot use t which is in time, to mix with pure numbers which in this case is grams. That means that both C and D are incorrect.

Now as with the last one, are you going to raise e to a minus number or a plus number? Remember that if e is raised to a plus number, the sample in this case will increase. You are watching a radioactive decay. The number has to be smaller. So B is eliminated. There is only one answer left and that's A. It should be correct.

A <<<<< answer

8 0

3 years ago