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timurjin [86]
3 years ago
8

The liquid volume of Eric's water bottle is 3 liters. What is the approximate liquid volume of 5 of these bottles in milliliters

? A) 15 kiloliters B) 150 milliliters C) 150 centiliters D) 15,000 milliliters E) 15,000 centiliters
Mathematics
1 answer:
stepan [7]3 years ago
6 0

Answer:

Option D is correct

The approximate liquid volume of 5 of these bottles is, 15,000 milliliters.

Step-by-step explanation:

Given the statement: The liquid volume of Eric's water bottle is 3 liters.

Using conversion:

1 liters = 1000 milliliters

Convert 3 liters into milliliters;

using above conversion:

3 liters  = 3 \times 1000 = 3000 milliliters.

To find the volume of liquid in 5 of these bottles in milliliters:

Volume of liquid in 1 bottle is, 3000 milliliters.

then;

Volume of liquid in 5 bottles  = 5 \times 3000 = 15,000 milliliters.

Therefore, approximate liquid volume of 5 of these bottles is, 15,000 milliliters

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Tomtit [17]

Answer:

1215 minutes are the possible numbers he has used his phone in a month.

Step-by-step explanation:

He has a monthly fee of 14$ then to the least that he has been charged we need to substract the monthly fee as follows:

Monthly charged = 74,75-14

Monthly charged= 60,75$

Then he pays an additional 0,05 $/minute of use, to know the consume:

Minutes= \frac{60,75}{0,05}

Minutes= 1215 possible numbers of minutes he has used his phone.

8 0
3 years ago
Solve this pls<br><br> 6i&lt;5i+3u
lions [1.4K]

i < 3u

Step-by-step explanation:

6i < 5i + 3u

6i - 5i < 3u

i < 3u

8 0
3 years ago
True or False: The variables in the equation 4x-(5y)2=64x-(5y)2=6 are 4, 5, and 6
aleksley [76]

Answer: False

Step-by-step explanation:

4x - (5y) 2 = 64x - (5y) 2 = 6

Identify the variables:

4x, 5y, 64x

So, it would actually be:

4, 5, and 64

6 0
3 years ago
Given the following three points, find by the hand the quadratic function they represent (0,6, (2,16, (3,33)
Lisa [10]

Answer:

f(x) = 4x^2 - 3x + 6

Step-by-step explanation:

Quadratic function is given as f(x) = ax^2 + bx + c

Let's find a, b and c:

Substituting (0, 6):

6 = a(0)^2 + b(0) + c

6 = 0 + 0 + c

c = 6

Now that we know the value of c, let's derive 2 system of equations we would use to solve for a and b simultaneously as follows.

Substituting (2, 16), and c = 6

f(x) = ax^2 + bx + c

16 = a(2)^2 + b(2) + 6

16 = 4a + 2b + 6

16 - 6 = 4a + 2b + 6 - 6

10 = 4a + 2b

10 = 2(2a + b)

\frac{10}{2} = \frac{2(2a + b)}{2}

5 = 2a + b

2a + b = 5 => (Equation 1)

Substituting (3, 33), and c = 6

f(x) = ax^2 + bx + x

33 = a(3)^2 + b(3) + 6

33 = 9a + 3b + 6

33 - 6 = 9a + 3b + 6 - 6

27 = 9a + 3b

27 = 3(3a + b)

\frac{27}{3} = \frac{3(3a + b)}{3}

9 = 3a + b

3a + b = 9 => (Equation 2)

Subtract equation 1 from equation 2 to solve simultaneously for a and b.

3a + b = 9

2a + b = 5

a = 4

Replace a with 4 in equation 2.

2a + b = 5

2(4) + b = 5

8 + b = 5

8 + b - 8 = 5 - 8

b = -3

The quadratic function that represents the given 3 points would be as follows:

f(x) = ax^2 + bx + c

f(x) = (4)x^2 + (-3)x + 6

f(x) = 4x^2 - 3x + 6

6 0
3 years ago
the tax on a property with an assessed value of $64,000 is $650. Using a proportion, find the tax on a property with an assessed
AVprozaik [17]
The answer is $1200.
5 0
3 years ago
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