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timurjin [86]
3 years ago
8

The liquid volume of Eric's water bottle is 3 liters. What is the approximate liquid volume of 5 of these bottles in milliliters

? A) 15 kiloliters B) 150 milliliters C) 150 centiliters D) 15,000 milliliters E) 15,000 centiliters
Mathematics
1 answer:
stepan [7]3 years ago
6 0

Answer:

Option D is correct

The approximate liquid volume of 5 of these bottles is, 15,000 milliliters.

Step-by-step explanation:

Given the statement: The liquid volume of Eric's water bottle is 3 liters.

Using conversion:

1 liters = 1000 milliliters

Convert 3 liters into milliliters;

using above conversion:

3 liters  = 3 \times 1000 = 3000 milliliters.

To find the volume of liquid in 5 of these bottles in milliliters:

Volume of liquid in 1 bottle is, 3000 milliliters.

then;

Volume of liquid in 5 bottles  = 5 \times 3000 = 15,000 milliliters.

Therefore, approximate liquid volume of 5 of these bottles is, 15,000 milliliters

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Can anyone help me with this?
Viktor [21]
E. 1/2
With trig functions, multiple x values correspond with the same y value.
Using an initial x value (the principle value), we can find other x values for the same y value, this is what we are are being asked to find in this question.
There are slightly different ways to find these x values (also known as solutions) for each of the basic trig functions.
The x values are in degrees for the basic trig functions.
For cosine, the rule is as follows:
360 - principle value;
this will give what I, personally, like to think of as a secondary principle value (this value is not actually recognised as a secondary principle value, I just like to think of it as such). Anyway, all other solutions can the be found by adding or substrating any integer multiple of 360 to/from the PV and 'secondary PV'.

For your question:
cos60 = 1/2
60 is the x value (PV)
so...
360 - 60 = 300 is the 'secondary PV'
Just to be clear, this means that if I were to find the cos300, I would get 1/2.

That is sufficient for explaining the answer to this particular question but if you wanted to find any other solution, you would just have to do either:
60 + or - n(360)
or...
300 + or - n(360),
where n = any integer
5 0
3 years ago
A student got 34 pencils for school. If she sharpen 16 of the pencils before school what is her ratio of unsharpened pencils to
belka [17]

34-16 = 18

 so 18 are unsharpened

ratio is 18/16 reduced to 9/8

8 0
3 years ago
Read 2 more answers
Find Sin (BAC+30) 80POINTS
Ann [662]

Answer:

\dfrac{2}{5}\sqrt{3}+\dfrac{3}{10}

Step-by-step explanation:

<u>Trigonometric Identities</u>

\sin (A \pm B)=\sin A \cos B \pm \cos A \sin B

<u>Trigonometric ratios</u>

\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Using the trig ratio formulas for cosine and sine:

  • \cos (\angle BAC)=\dfrac{12}{20}
  • \sin (\angle BAC)=\dfrac{16}{20}

<u>Angles</u>

\sin (30^{\circ})=\dfrac{1}{2}

\cos (30^{\circ})=\dfrac{\sqrt{3}}{2}

Therefore, using the trig identities and ratios:

\begin{aligned}\sin (\angle BAC + 30^{\circ}) & = \sin (\angle BAC) \cos (30^{\circ})+\cos (\angle BAC) \sin (30^{\circ})\\\\& = \dfrac{16}{20} \cdot \dfrac{\sqrt{3}}{2} + \dfrac{12}{20} \cdot \dfrac{1}{2}\\\\& = \dfrac{16}{40}\sqrt{3}+\dfrac{12}{40}\\\\& = \dfrac{2}{5}\sqrt{3}+\dfrac{3}{10}\end{aligned}

3 0
1 year ago
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Will give brainliest if helpful!!!!! :)
dolphi86 [110]

Answer:

I hope this help

Step-by-step explanation:

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7 0
2 years ago
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Is this congruent by SSS, SAS, AAS, ASA??
sleet_krkn [62]

Answer:

sss

Step-by-step explanation:

6 0
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