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inessss [21]
4 years ago
9

Convert 3.5 in to a fraction with 5 repeating

Mathematics
2 answers:
lana [24]4 years ago
7 0
35/100
Then you'd have to simplify, and it should be 7/20
Usimov [2.4K]4 years ago
3 0
3 5/10 or 3 1/2 would be the answer to your question.
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Five years ago, Chris opened a savings account that earned 1.4% simple interest every year. He opened his account with $850.00 a
Blababa [14]
If it is compounded annually, this will be 850(1.014)^5 which equals $911.19
3 0
3 years ago
If all seats were sold for this flight, what would be the total airline income for the seats?
Gekata [30.6K]

Answer:

$90,200

Step-by-step explanation:

Airlines usually try to sell their all seats before they fly the airplane. They do wish to sell maximum available seats in order to maximize their revenue. If the airplane takes off with less occupancy then there is opportunity cost for the airline companies. There are 200 seats available to the current flight and they wishes to sell it completely. If they sell all the 200 seats at the price of $451 per seat then their total revenue will be $90,200.

7 0
3 years ago
Please help i will give brainliest
Lilit [14]

Answer:

c

Step-by-step explanation:

7 0
3 years ago
Worth 20 points
sladkih [1.3K]
D(X+2)(2X+1) This is your answer. 

3 0
4 years ago
What are the possible rational roots of the polynomial equation?<br><br> 0=2x7+3x5−9x2+6
RoseWind [281]

Answer: \pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

a_nx^n +a_{n- 1}x^{n - 1} + … + a_1x^1 + a_0 = 0

Where:

- The coefficients are integers.

- a_n is the leading coeffcient (a_n\neq 0)

- a_0 is the constant term a_0\neq 0

Every rational root of the polynomial is in the form:

\frac{p}{q}=\frac{\pm(factors\ of\ a_0)}{\pm(factors\ of\ a_n)}

For the case of the given polynomial:

2x^7+3x^5-9x^2+6=0

We can observe that:

- Its constant term is 6, with factors 1, 2 and 3.

- Its leading coefficient is 2, with factors 1 and 2.

 Then, by Rational Roots Test we get the possible rational roots of this polynomial:

\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

5 0
3 years ago
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