Answer: a. 1.981 < μ < 2.18
b. Yes.
Step-by-step explanation:
A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.
First, we calculate mean of the sample:
2.08
Now, we estimate standard deviation:
s = 0.1564
For t-score, we need to determine degree of freedom and 
:
df = 12 - 1
df = 11
= 1 - 0.95
α = 0.05
0.025
Then, t-score is
= 2.201
The interval will be
± 
2.08 ± 
2.08 ± 0.099
The 95% two-sided CI on the mean is 1.981 < μ < 2.18.
B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.
It should be 12×18. 1:3 means you take where it's at, at 1 and multiply it's size by 3.
4500 = 4.5 * 10^3
57 = 5.7 * 10^1
730 = 7.3 * 10^2
0.007 = 7 * 10^-3
300.25 = 3.0025 * 10^2
56,325.2 = 5.63252 * 10^4
Answer:
24.6
Step-by-step explanation:
you multiply them all by two then add them together. :P
Answer:
Step-by-step explanation:
Simplifying
6 = 1 + -2n + 5
Reorder the terms:
6 = 1 + 5 + -2n
Combine like terms: 1 + 5 = 6
6 = 6 + -2n
Add '-6' to each side of the equation.
6 + -6 = 6 + -6 + -2n
Combine like terms: 6 + -6 = 0
0 = 6 + -6 + -2n
Combine like terms: 6 + -6 = 0
0 = 0 + -2n
0 = -2n
Solving
0 = -2n
Solving for variable 'n'.
Move all terms containing n to the left, all other terms to the right.
Add '2n' to each side of the equation.
0 + 2n = -2n + 2n
Remove the zero:
2n = -2n + 2n
Combine like terms: -2n + 2n = 0
2n = 0
Divide each side by '2'.
n = 0
Simplifying
n = 0
