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Yuliya22 [10]
2 years ago
8

A van drove 241. 92 miles on 10. 8 gallons of gas. How far could the van drive on a full tank of 16. 2 gallons of gas? Drag and

drop a number to correctly complete the statement. The van could drive Response area miles on a full tank of gas.
Mathematics
1 answer:
mrs_skeptik [129]2 years ago
8 0

You can use the given data to find out how many miles does the van travels for 1 gallon of gas. This will help you get the distance van can travel for full tank (16.2 gallons) of gas.

The considered van with full tank(16.2 gallons) can travel 362.88 miles

<h3>How to find the distance the van can travel per gallon of gas?</h3>

Since the considered van traveled 241.92 miles in 10.8 gallons, then we can take equal in dimension of input and output relation.

10.8 \: \rm gallons = 241.92 \: miles\\\\\text{Dividing both quantities by 10.8 to get miles traveled per gallon}\\\\\dfrac{10.8}{10.8} \:  gallon = \dfrac{241.92}{10.8} \: miles\\\\ 1 \: gallon = 22.4 \: miles

Thus, the considered van travels 22.4 miles per gallon of gas.

Now, since full tank consists of 16.2 gallons, thus, multiplying by 16.2 on both the sides, we  get

\rm 1 \: gallon = 22.4 \: miles\\\\16.2 \: gallons  = 16.2 \times 22.4 \: miles = 362.88 \: miles

Thus,

The considered van with full tank(16.2 gallons) can travel 362.88 miles

Learn more about division here:

brainly.com/question/2689177

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For this case, the first thing we must do is define variables:
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The maximum number of pillowcases she could have purchased is:
 
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10*(9-5)

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Write the given second order equation as its equivalent system of first order equations. u′′−5u′−4u=1.5sin(3t),u(1)=1,u′(1)=2.5
lakkis [162]

Answer:

hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to

Answer:  v = 5v + 4u + 1.5sin(3t),

  • 0
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Step-by-step explanation:

u" - 5u' - 4u = 1.5sin(3t)        where u'(1) = 2.5   u(1) = 1

v represents the "velocity function"   i.e   v = u'(t)

As v = u'(t)

<em>u' = v</em>

since <em>u' = v </em>

v' = u"

v'  = 5u' + 4u + 1.5sin(3t)   ( given that u" - 5u' - 4u = 1.5sin(3t) )

    = 5v + 4u + 1.5sin(3t)  ( noting that v = u' )

so v' = 5v + 4u + 1.5sin(3t)

d/dt \left[\begin{array}{ccc}u&\\v&\\\end{array}\right]= \left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]  \left[\begin{array}{ccc}u&\\v&\\\end{array}\right] + \left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]

Given that u(1) = 1 and u'(1) = 2.5

since v = u'

v(1) = 2.5

note: the initial value for the vector valued function is given as

\left[\begin{array}{ccc}u(1)&\\v(1)\\\end{array}\right]  = \left[\begin{array}{ccc}1\\2.5\\\end{array}\right]

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Keith_Richards [23]
Answer: the lines are not parallel.


Explanation: if you isolate the x in 3x^2-4y=-1, the equation is y=3/4x^2+1/4


So, they are not parallel because the slope is not the same.
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2 years ago
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