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laila [671]
3 years ago
5

8/12A) Horace has a comparative advantage in both tasks. B) Tammi has a comparative advantage in both tasks. C) Horace has a com

parative advantage in grooming dogs and Tammi in bathing cats. D) Horace has a comparative advantage in bathing cats and Tammi in grooming dogs.
Chemistry
2 answers:
lilavasa [31]3 years ago
6 0
Comparative and similar advantages
MArishka [77]3 years ago
4 0

Answer:

B) Tammi has a comparative advantage in both tasks.

Explanation:

Based on the information provided in the question, Horace does not have the total advantage in the grooming of dogs as well as the bathing of cats due to the opportunity cost. On the other hand, Tammi has the total advantage of the bathing of cats as well as the grooming of dogs due to the opportunity cost. Therefore, the correct option is option B.

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Answer:

isobars

Explanation:

How?

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Part a use these data to calculate the heat of hydrogenation of buta-1,3-diene to butane. c4h6(g)+2h2(g)→c4h10(g)
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<u>Answer:</u> The heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H

The equation used to calculate enthalpy change is of a reaction is:

\Delta H_{rxn}=\sum [n\times \Delta H_{(product)}]-\sum [n\times \Delta H_{(reactant)}]

For the given chemical reaction:

C_4H_6(g)+2H_2(g)\rightarrow C_4H_{10}(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(1\times \Delta H_{(C_4H_{10})})]-[(1\times \Delta H_{(C_4H_6)})+(2\times \Delta H_{(H_2)})]

We are given:

\Delta H_{(C_4H_{10})}=-2877.6kJ/mol\\\Delta H_{(C_4H_6)}=-2540.2kJ/mol\\\Delta H_{(H_2)}=-285.8kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(1\times (-2877.6))]-[(1\times (-2540.2))+(2\times (-285.8))]\\\\\Delta H_{rxn}=234.2J

Hence, the heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

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