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lys-0071 [83]
3 years ago
14

Which of the following is true of gases

Chemistry
1 answer:
yuradex [85]3 years ago
7 0

4?

Explanation:

i think its 4, i might be wrong.

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What is a nonpolar bond?
serious [3.7K]
A bond between 2 nonmetal atoms that have the same electronegativity and therefore have equal sharing of the bonding electron pairExample: In H-H each H atom has an electronegativity value of 2.1, therefore the covalent bond between them is considered nonpolar. Nonpolar covalent bonds, with equal sharing of the bond electrons, arise when the electronegativities of the two atoms are equal.

 

8 0
3 years ago
Read 2 more answers
4. Which of the following NOT TRUE about real gas
Semenov [28]

Answer:

The answer is D.

Explanation:

Intermolecular force are negligible

When the distance between molecules decrease,

the attraction or repulsion become greater

7 0
2 years ago
What is the chemical formula for a molecule of salt?
BARSIC [14]

Answer:

Su fórmula molecular es Na Cl y es el producto de la base hidróxido sódico (NaOH) y ácido clorhídrico, H Cl. En general, las sales son compuestos iónicos que forman cristales. Son generalmente solubles en agua, donde se separan los dos iones. Las sales típicas tienen un punto de fusión alto, baja dureza, y baja compresibilidad.

Explanation:

5 0
2 years ago
A) Find the gas speed of sulfur dioxide at 100.0 degrees Celsius? ______________
gtnhenbr [62]

a. 381.27 m/s

b. the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triiodide

<h3>Further explanation</h3>

Given

T = 100 + 273 = 373 K

Required

a. the gas speedi

b. The rate of effusion comparison

Solution

a.

Average velocities of gases can be expressed as root-mean-square averages. (V rms)  

\large {\boxed {\bold {v_ {rms} = \sqrt {\dfrac {3RT} {Mm}}}}

R = gas constant, T = temperature, Mm = molar mass of the gas particles  

From the question  

R = 8,314 J / mol K  

T = temperature  

Mm = molar mass, kg / mol  

Molar mass of Sulfur dioxide = 64 g/mol = 0.064 kg/mol

\tt v=\sqrt{\dfrac{3\times 8.314\times 373}{0.064} }\\\\v=381.27~m/s

b. the effusion rates of two gases = the square root of the inverse of their molar masses:  

\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

M₁ = molar mass sulfur dioxide = 64

M₂ =  molar mass nitrogen triodide = 395

\tt \dfrac{r_1}{r_2}=\sqrt{\dfrac{395}{64} }=\dfrac{20}{8}=2.5

the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triodide

4 0
3 years ago
????????????????????????????
aliina [53]

Answer:

<h2>The answer you are looking for is (B)</h2>

Explanation:

hope this helps

<h2>please mark as brainliest!!!</h2>
8 0
3 years ago
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