Answer:
The heat required to change 25.0 g of water from solid ice to liquid water at 0°C is 8350 J
Explanation:
The parameters given are
The temperature of the solid water = 0°C
The heat of fusion, = 334 J/g
The heat of vaporization, = 2260 J/g
Mass of the solid water = 25.0 g
We note that the heat required to change a solid to a liquid is the heat of fusion, from which we have the formula for heat fusion is given as follows;
ΔH = m ×
Therefore, we have;
ΔH = 25 g × 334 J/g = 8350 J
Which gives the heat required to change 25.0 g of water from solid ice to liquid water at 0°C as 8350 J.
Answer: 88g
Explanation:
11 moles H2 = 11 mole H2O = 5.5 moles O2 = 16*5.5 g
Answer:
The mass of gas is 30.02 g.
Explanation:
Given data:
Volume of gas = 22.4 L
Density of gas = 1.34 g/L
Mass of gas = ?
Solution:
The given problem will be solved through density formula.
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
Now we will put the values in formula.
1.34 g/L = m /22.4 L
m = 1.34 g/L × 22.4 L
m = 30.02 g
The mass of gas is 30.02 g.
it doesn't repopulate as fast because ecosystem 2 could have more trouble reproducing then ecosystem 1.
