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jasenka [17]
3 years ago
11

The table shows different quantities of flour and the number of cookies that can be made with each quantity of flour. If the rel

ationship between the cups of flour and the number of cookies is proportional, find the value of x.
Flour (cups) 3 6 12
Cookies (dozens) 4 x 16
Question 9 options:

A)

12


B)

7


C)

8


D)

10

Mathematics
2 answers:
kvv77 [185]3 years ago
5 0

Answer:

C:8

Step-by-step explanation:

kow [346]3 years ago
4 0
C) 8 is the appropriate choice

4 dozen are made from 3 cups of flour, so twice that flour (6 cups) will produce twice the number of cookies, 8 dozen.
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Clark spent a total of $52 on a pair of shoes and a new jacket. The shoes cost $4 more than the jacket. Write a system of equati
lara [203]

Answer:

  • x+y=52
  • x-y=4
  • y=24

Step-by-step explanation:

The sum of the two costs is $52, so we can write ...

  x + y = 52

The shoes cost $4 more than the jacket, so we can write ...

  x - y = 4

These are your system of equations.

__

Subtract the second equation from the first:

  (x +y) -(x -y) = (52) -(4)

  2y = 48 . . . . . simplify

  y = 24 . . . . . . .divide by 2

The cost of the jacket is $24.

8 0
3 years ago
Use the following matrices, A, B, C and D to perform each operation.
Vinvika [58]

Step-by-step explanation:

A=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]

B=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]

C=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]

D=\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]

1.\\A+B=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]+\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]=\left[\begin{array}{ccc}3+4&1+1\\5+6&7+0\end{array}\right]=\left[\begin{array}{ccc}7&2\\11&7\end{array}\right]

2.\\B-A=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]-\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]=\left[\begin{array}{ccc}4-3&1-1\\6-5&0-7\end{array}\right]=\left[\begin{array}{ccc}1&0\\1&-7\end{array}\right]

3.\\3C=3\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]=\left[\begin{array}{ccc}(3)(-2)&(3)(3)&(3)(1)\\(3)(-1)&(3)(0)&(3)(4)\end{array}\right]=\left[\begin{array}{ccc}-6&9&3\\-3&0&12\end{array}\right]

4.\\C\cdot D=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]\cdot\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]\\\\=\left[\begin{array}{ccc}(-2)(-2)+(3)(0)+(1)(3)&(-2)(3)+(3)(-2)+(1)(4)&(-2)(4)+(3)(1)+(1)(-1)\\(-1)(-2)+(0)(0)+(4)(3)&(-1)(3)+(0)(-2)+(4)(4)&(-1)(4)+(0)(1)+(4)(-1)\end{array}\right]\\=\left[\begin{array}{ccc}7&-8&-6\\14&13&-8\end{array}\right]

5.\\2D+3C\\\text{This operation can't be performed because the matrices}\\\text{ are of different dimensions.}

6 0
3 years ago
If the measure angle 1=40, what is the measure angle of 3?<br> A. 80 <br> b. 40<br> c. 10<br> d. 100
iren2701 [21]
D. 100 is the answer
5 0
3 years ago
|(-10)+25)|=<br> PLZZ HELP AND THANK YOU!!!&lt;3
NNADVOKAT [17]
-15 because there is ten before 25
6 0
2 years ago
You have a garden in your backyard that measures 15 meters by 20 meters. You want to place stepping stones around the perimeter
Anettt [7]

Answer:

0.5 m

Step-by-step explanation:

Given that the dimensions of the garden are 15 meters by 20 meters.

The area of the new garden (original garden + stone placed around the perimeter) is 336m².

Let d be the width of the border having stepping stones as shown in the figure. The shaded region in the figure is the area having stepping stones.

The area including the shaded region = (15+2d)(20+2d) m^2

\Rightarrow 336  = (15+2d)(20+2d) \\\\\Rightarrow 336  = 300+ 70 d +4d^2 \\\\\Rightarrow 4d^2 +70d+300-336=0 \\\\\Rightarrow 4d^2 +70d-36=0 \\\\\Rightarrow 2d^2 +35d-18=0 \\\\\Rightarrow 2d^2 +36d-d-18=0 \\\\\Rightarrow (2d-1)(d+18)=0 \\\\\Rightarrow (2d-1)=0, \; or \; (d+18) \\\\\Rightarrow d= 0.5\;or -18 \\\\

As the width of the stone border can't be a negative value, so taking the positive value.

Hence, the width of the stone border is 0.5 m.

So, the wi

7 0
3 years ago
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