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3 years ago

This makes no sense to me keep getting the wrong answers when i try to figure it out

Mathematics

1 answer:

satela [25.4K]3 years ago

4 0

To solve this problem, you'd want to start by finding the mean of the given numbers. To find the mean, add all the numbers together and divide by how many there are.

Next, you'll see that the question says one of the rents changes from $1130 to $930. So find the mean of all the numbers again, except include $930 in your calculation instead of $1130.

I got $990 as the mean for the given numbers, and $970 as the mean after replacing the $1130 with $930. Subtracting the two means gives you $20. So the mean decreased by $20.

Now for the median, all you need to do is find the median of the given numbers and compare them with the median of the new data. Because there are ten terms, you have to add the middle two numbers and divide by two. $990 + $1020 = 2010. 2010÷2 = $1005 as the first median.

The new rent is 930, so you have to reorder the data so it goes from least to greatest again. 745, 915, 925, 930, 965, 990, 1020, 1040, 1050, 1120. After finding the median again you get 977.5. Subtracting the two medians gives you $27.5 as how much the median decreased. Hope this helps!

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4x+5y-5z=196 -11x-7y+12z=-211 -8x-9y-z=-236 Solve for x y z

FrozenT [24]

Have you learned matrices yet? I'm going to use that to solve these, please refer to the photos.

I solved the system by using a matrix calculation. The work always needs to be shown and you do that by setting up the matrix like in the first photo and also writing out all your equations. In a TI calculator, to do this you press 2ND-X^-1,GO TO EDIT - [A] - 3×4- now enter the coefficient of the system of equations variables. NOW 2ND MODE- 2ND-X^-1 -GO TO MATH- ALPHA APPS

Now, if you don't know this you may be confuse so after rref([A]) was enter a matrix came up with [1 0 0 -21] in the top row this means x equal -21. So, the next row is y and it came out as [0 1 0 46] so y equals 46 and I'm going to let you figure out what z is by looking at the matrix.

SO... X=-21 Y=46 and Z=-10

Let's Test it

$4x + 5y - 5z = 196 \\ 4( - 21) + 5(46) - 5( - 10) = 196 \\ - 84 + 230 + 50 = 196 \\ 196 = 196$

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3 years ago

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Seventy million pounds of trout are grown in the U.S. every year. Farm-raised trout contain an average of grams of fat per pound

STatiana [176]

Complete question is:

Seventy million pounds of trout are grown in the U.S. every year. Farm-raised trout contain an average of 32 grams of fat per pound, with a standard deviation of 7 grams of fat per pound. A random sample of 34 farm-raised trout is selected. The mean fat content for the sample is 29.7 grams per pound. Find the probability of observing a sample mean of 29.7 grams of fat per pound or less in a random sample of 34 farm-raised trout. Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.

Answer:

Probability = 0.0277

Step-by-step explanation:

We are given;

Mean: μ = 32

Standard deviation;σ = 7

Random sample number; n = 34

To solve this question, we would use the equation z = (x - μ)/(σ/√n) to find the z value that corresponds to 29.7 grams of fat.

Thus;

z = (29.7 - 32)/(7/√34)

Thus, z = -2.3/1.200490096

z = -1.9159

From the standard z table and confirming with z-calculator, the probability is 0.0277

Thus, the probability to select 34 fish whose average grams of fat per pound is less than 29.7 = 0.0277

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3 years ago

Bath and 1 yard of ribbon. She is 1/2 yard for project. She wants to divide the rest of the ribbon into pieces 1/4 yards long. H

ikadub [295]

Answer:

Step-by-step explanation:

Given:

Total length of ribbon = 1 yard

Length of ribbon used for project = $\frac{1}{2}$ yard

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To find:

The number of ribbons of length $\frac{1}{4}$ yard that can be made = ?

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Length of ribbon left after the 1 yard ribbon is used for project can be calculated by subtracting the length of ribbon used from the initial length of ribbon.

i.e.

Length of ribbon left = $1-\frac{1}{2} =\frac{1}{2}$ yard

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i.e.

Number of ribbons:

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