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3 years ago

This makes no sense to me keep getting the wrong answers when i try to figure it out

Mathematics

1 answer:

satela [25.4K]3 years ago

4 0

To solve this problem, you'd want to start by finding the mean of the given numbers. To find the mean, add all the numbers together and divide by how many there are.

Next, you'll see that the question says one of the rents changes from $1130 to $930. So find the mean of all the numbers again, except include $930 in your calculation instead of $1130.

I got $990 as the mean for the given numbers, and $970 as the mean after replacing the $1130 with $930. Subtracting the two means gives you $20. So the mean decreased by $20.

Now for the median, all you need to do is find the median of the given numbers and compare them with the median of the new data. Because there are ten terms, you have to add the middle two numbers and divide by two. $990 + $1020 = 2010. 2010÷2 = $1005 as the first median.

The new rent is 930, so you have to reorder the data so it goes from least to greatest again. 745, 915, 925, 930, 965, 990, 1020, 1040, 1050, 1120. After finding the median again you get 977.5. Subtracting the two medians gives you $27.5 as how much the median decreased. Hope this helps!

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The answer to this question please

cestrela7 [59]

If its to number 9, it's ∈35.48

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3 years ago

on an avrage saturday, 15% of tickets sold are child tickes. if there were 460 tickets sold on saturday then how many were sold

Ede4ka [16]

Answer:

69 child tickets

Step-by-step explanation:

0.15 x 460 = 69

8 0

3 years ago

Growth Models 19515. In 1968, the U.S. minimum wage was $1.60 per hour. In 1976, the minimum wagewas $2.30 per hour. Assume the

VikaD [51]

In general, the exponential growth function is given by the formula below

$f(x)=a(1+r)^x$

Where a and r are constants, and x is the number of time intervals.

In our case, n=0 for 1960; therefore, 1968 is n=8,

$\begin{gathered} f(8)=a(1+r)^8 \\ \text{and} \\ f(8)=1.6 \\ \Rightarrow1.6=a(1+r)^8 \end{gathered}$

And 1976 is n=16

$\begin{gathered} f(16)=a(1+r)^{16} \\ \text{and} \\ f(16)=2.3 \\ \Rightarrow2.3=a(1+r)^{16} \end{gathered}$

Solve the two equations simultaneously, as shown below

$\begin{gathered} \frac{1.6}{(1+r)^8}=a \\ \Rightarrow2.3=\frac{1.6}{(1+r)^8}(1+r)^{16} \\ \Rightarrow2.3=1.6(1+r)^8 \\ \Rightarrow\frac{2.3}{1.6}=(1+r)^8 \\ \Rightarrow(\frac{2.3}{1.6})^{\frac{1}{8}}=(1+r)^{}^{} \\ \Rightarrow r=(\frac{2.3}{1.6})^{\frac{1}{8}}-1 \\ \Rightarrow r=0.0464078 \end{gathered}$

Solving for a,

$\begin{gathered} r=0.0464078 \\ \Rightarrow a=\frac{1.6}{(1+0.0464078)^8}=1.113043\ldots \end{gathered}$

a) Thus, the equation is

$\Rightarrow f(n)=1.113043\ldots(1+0.0464078\ldots)^n$

b) 1960 is n=0; thus,

$f(0)=1.113043\ldots(1+0.0464078\ldots)^0=1.113043\ldots$

The answer to part b) is $1.113043... per hour

c)1996 is n=36

$\begin{gathered} f(36)=1.113043\ldots(1+0.0464078\ldots)^{36} \\ \Rightarrow f(36)=5.6983\ldots \end{gathered}$

The model prediction is above $5.15 by $0.55 approximately. The answer is 'below'

4 0

1 year ago

Sebastian writes the recursive formula f(x+1) = 4f(x) to represent a geometric sequence whose second term is 12. Which explicit

NeX [460]

Answer:

B.) f(x) = 3(4)x − 1

Step-by-step explanation:

A) f(x) = 12(4)x

B.) f(x) = 3(4)x − 1

C.) f(x) = 4(12)x

D.) f(x) = 4(3)x − 1

Given:

f(x+1) = 4f(x)

f(2)=12

f(2) = 12

f(3) = 4f(2) = 4 * 12 = 48

f(3)=48 and f(2)=12

From f(3)=48 and f(2)=12

r=48/12

r=common ratio

Recall,

f(2)=12=ar

r=4

f(2)=ar=12

a*4=12

a=12/4

a=3

an=ar^(n-1)

For x term

an=3*4(x-1)

B.) f(x) = 3(4)x − 1

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4 years ago

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