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Darina [25.2K]
3 years ago
12

Write an algebraic expression to represent each verbal expression.

Mathematics
1 answer:
Nina [5.8K]3 years ago
6 0
Question (1):
Assume that the number is x
We want to get: <span>four times the sum of x and 3
This means that we would add x and 3 first and then multiply the result by 4.
The algebraic expression would be as follows:
4(x+3)

Question (2):
Assume that the number is x.
We want to get: </span><span>7 less than fifteen times x
This means that we would multiply the x by 15 and then subtract 7 from the product.
The algebraic expression would be as follows:
15x - 7

Question (3):
Assume that the number is x.
We want to get: </span><span>the difference of nine times x and the quotient of 6 and x 
This means that:
i- We would first multiply 9 by the number x
ii- Then we would divide 6 by x
iii- Finally we will subtract the quotient (step ii) from the product (step i)
</span>The algebraic expression would be as follows:
(9x) - (6/x)

Question (4):
Assume that the number is x.
We want to get: <span>the sum of 100 and four times a number
This meas that we would first multiply 4 by x and then add 100 to the product.
The algebraic expression would be as follows:
4x + 100

Question (5):
Assume that the number is x.
We want to get: </span><span>the product of 3 and the sum of 11 and x
This means that we would first add 11 to the number x and then multiply the result by 3
The algebraic expression would be as follows:
3(11+x)

Question (6):
Assume that the number is x.
We want to get: </span><span>four times the square of x increased by five times x
This means that:
i- We would square the x first
ii- multiply the result from step i by 4
iii- multiply 5 by x
iv- add the result from step ii to the result from step iii
The algebraic expression would be as follows:
4x^2 + 5x

Question (7):
Assume that the number is x.
We want to get: </span><span>23 more than the product of 7 and x
This means that we would multiply x by 7 and then add 23 to the product
The algebraic expression would be as follows:
7x+23

Hope this helps :)</span>
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Maya runs a farm stand that sells raspberries and blueberries. Each pound of raspberries sells for $1 and each pound of blueberr
aniked [119]

30 pounds of raspberries and 50 pounds of blueberries are sold

<em><u>Solution:</u></em>

Let "a" be the pounds of raspberries sold

Let "b" be the pounds of blueberries sold

Cost per pound of raspberry = $ 1

Cost per pound of blue berry = $ 3.25

<em><u>Maya made $192.50 from selling a total of 80 pounds of raspberries and blueberries</u></em>

Therefore,

a + b = 80

a = 80 - b ------- eqn 1

<em><u>Maya made $192.50. Therefore, frame a equation as:</u></em>

pounds of raspberries sold x Cost per pound of raspberry + pounds of blueberries sold x Cost per pound of blue berry = 192.50

a \times 1 + b \times 3.25 = 192.50

a + 3.25b = 192.50 ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Substitute eqn 1 in eqn 2</u></em>

80 - b + 3.25b = 192.50

2.25b = 192.50 - 80

2.25b = 112.5

Divide both sides by 2.25

b = 50

<em><u>Substitute b = 50 in eqn 1</u></em>

a = 80 - 50

a = 30

Thus 30 pounds of raspberries and 50 pounds of blueberries are sold

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3 years ago
What is the supplement of 123°
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Since (x - 2)° and (2x + 5)° represent a pair of supplementary angles, then their sum must be equal to 180°. Therefore, the two supplementary angles are 57° and 123°.
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The width of the fountain in Luke's drawing from the example is 2 cm. What is the width of the fountain in Isabella's scale draw
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Answer:

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5x<br> 3.<br> +<br> 4x2-9<br> 2x+1<br> 2x2+x-3
irakobra [83]

Answer:

~Re-write the equation~

SOLVE:

5x(3)+4x (2-9)+(2x+1)+(2x2+x-3)

5(1)(3)=15

4(2-9)=8+36=44

2x+1=3

2x2+x-3:4(1)-3=1

15+44+3+1

ANSWER=63x

Step-by-step explanation:

I wasn't quite sure because of the way you wrote it but here's an answer!

7 0
3 years ago
Simplify the expression:<br><br> 3x (4x-6)<br> —————<br> 2x(3x)
Marina86 [1]

Answer:

=\frac{2x-3}{x}

Step-by-step explanation:

=6x^2\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=\frac{3x\left(4x-6\right)}{2x\cdot \:3x}\\2x\cdot \:3x=6x^2\\=\frac{3x\left(4x-6\right)}{6x^2}\\\mathrm{Cancel\:}\frac{3x\left(4x-6\right)}{6x^2}:\quad \frac{4x-6}{2x}\\=\frac{4x-6}{2x}\\\mathrm{Factor}\:4x-6:\quad 2\left(2x-3\right)\\=\frac{2\left(2x-3\right)}{2x}\\\mathrm{Divide\:the\:numbers:}\:\frac{2}{2}=1\\=\frac{2x-3}{x}

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3 years ago
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