The perimeter of the entire figure is 62.8 cm.
Given, that the diameter of the inner semicircles is 9 cm and the width between the outer and inner semicircles is 2 cm.
The radius of the inner semicircle =4.5 cm and the radius of outer semicircle =5.5 cm (∵Diameter=9+2=11 cm)
We need to find the perimeter of the entire figure.
<h3>What is the perimeter?</h3>
A perimeter is a closed path that encompasses, surrounds, or outlines either a two-dimensional shape or a one-dimensional length. The perimeter of a circle or an ellipse is called its circumference.
We know that, the circumference of a semicircle=πr and the circumference of two semicircles=2πr
Thus, the circumference of inner semicircles=2×3.14×4.5=28.26 cm
The circumference of outer semicircles=2×3.14×5.5=34.54 cm
The perimeter of the entire figure=28.26+34.54=62.8 cm
Therefore, the perimeter of the entire figure is 62.8 cm.
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It is being distributed ( ex: 5(1), bring the 5 over and multiply: 5). Since -1 is the term that is distributing for both 8m and 32, multiplying both would equal= -8m (8m x -1, + x - = negative), +32 (notice the positive, - x - = positive). In conclusion, this would be -8m+32.
The second number after the decimal is the hundredths place. To round to that place, you look at the number after it. In this case 6 is the hundredths place and 5 is the number after it. If the number after it is 5 or higher, the hundredths place number increases by 1, if it is less than 5 the hundredths place number doesn't change. So the answer is 8.47.
Answer:
(1)25 pound bag (2) 10 pound bags and(1) 5 pound bag
Step-by-step explanation:
There are six sides on each die. For each possible score on Die 1, there are six possible scores on Die 2. So the number of possible combinations is 6*6 = 36.
<span>It follows that if the dice are thrown 36 times, you would expect each combination to come up once. </span>
<span>We therefore simply need to know how many combinations add up to less than 5. (I've interpreted this as not including a total of 5 itself). </span>
<span>These combinations are: 1 and 1, 2 and 1, 1 and 2, 2 and 2, 3 and 1, and 1 and 3 ---> six combinations out of 36. </span>
<span>So you'd expect a sum less than 5 six times. </span>