Answer:
360 mi/h
Step-by-step explanation:
The speed for the outbound trip was ...
speed = distance/time = (715 mi)/(2 1/6 h) = 330 mi/h
The inbound speed was ...
(715 mi)/(1 5/6 h) = 390 mi/h
The airspeed of the plane is the average of these two ground speeds, so is ...
(330 +390)/2 = 360 . . . . mi/h
X
+
6
−
5
=
8
−
2
+
6
−
5
=
8
−
2
Solve
1
Subtract the numbers
x
+
6
−
5
=
8
−
2
+
6
−
5
=
8
−
2
x
+
1
=
8
−
2
+
1
=
8
−
2
2
Subtract the numbers
x
+
1
=
8
−
2
+
1
=
8
−
2
x
+
1
=
6
+
1
=
6
3
Subtract
1
1
from both sides
x
+
1
=
6
+
1
=
6
x
+
1
−
1
=
6
−
1
+
1
−
1
=
6
−
1
4
Simplify
Subtract the numbers
Subtract the numbers
x
=
5
=
5
Answer:
3
Step-by-step explanation:
the answer to 3 times 1 is 3
Answer:
= 18x + 4y hope this helps :)
Step-by-step explanation:
