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ololo11 [35]
3 years ago
10

If x=2k + 1, y=k - 1 is a solution of the equation 2x - 3y + 5=0. find the value of k.​

Mathematics
2 answers:
Ivenika [448]3 years ago
8 0
Value of k is -12.....


Merry Christmas

devlian [24]3 years ago
7 0

Answer:

x = 2k + 1 \\ y = k - 1 \\ given

if u substitute the givens in the eqn we will get..

2(2k + 1) - 2(k - 1) + 5 = 0 \\ 4k + 2 - (2k - 2) + 5 = 0 \\ 4k + 2 - 2k + 2 + 5 = 0 \\

then collect like terms

4k - 2k + 2 + 2 + 5 = 0 \\ 2k + 4 + 5 = 0 \\ 2k + 9 = 0

2k =  - 9 \\ k =  \frac{ - 9}{2}

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Answer:

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Hint: | Starting with zero, raise 7 to increasingly larger integer powers until the result exceeds 206.

Determine the powers of 7 that will be used as the places of the digits in the base-7 representation of 206:

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3 | 7^3 | 343

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Hint: | The powers of 7 (in ascending order) are associated with the places from right to left.

Label each place of the base-7 representation of 206 with the appropriate power of 7:

Place | | | 7^2 | 7^1 | 7^0 |  

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206_10 | = | ( | __ | __ | __ | )_(_7)

Hint: | Divide 206 by 7 and find the remainder. The remainder is the first digit from the right.

Determine the value of the first digit from the right of 206 in base 7:

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Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | __ | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 29, by 7 and find the remainder. The remainder is the next digit.

Determine the value of the next digit from the right of 206 in base 7:

29/7=4 with remainder 1

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | __ | 1 | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 4, by 7 and find the remainder. The remainder is the last digit.

Determine the value of the last remaining digit of 206 in base 7:

4/7=0 with remainder 4

Place | | | 7^2 | 7^1 | 7^0 |  

| | | ↓ | ↓ | ↓ |  

206_10 | = | ( | 4 | 1 | 3 | )_(_7)

Hint: | Express 206_10 in base 7.

The number 206_10 is equivalent to 413_7 in base 7.

Answer: 206_10 =413_7

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