Answer:
I believe it’s $41,500
Step-by-step explanation:
Given:
Consider the below figure attached with this question.
To find:
The solution to this linear system.
Solution:
From the below graph it is clear that both lines intersect each other at point (2,3).
Here,
x-coordinate = 2
y-coordinate = 3
Therefore, the solution to the given system is (2,3).
Hence, the required answer for first blank is 2 and for second blank is 3.
X and y represent the two students.
Teacher wants to spend at least $5 in each of x and y. That means x or y could be either equal to 5 or higher than 5.
x ≥ 5
y ≥ 5
Teacher only spends under $30. That means the sum of x and y couldn't be equal to higher than 30. It should be lower than 30.
x + y < 30
The correct answer is option D
Hello,
y+9=(x-10)*(-2)
==>y=-2x+11
Answer D if you put an "+" betheen y and 9 !!!!!!
Answer:Your left hand side evaluates to:
m+(−1)mn+(−1)m+(−1)mnp
and your right hand side evaluates to:
m+(−1)mn+(−1)m+np
After eliminating the common terms:
m+(−1)mn from both sides, we are left with showing:
(−1)m+(−1)mnp=(−1)m+np
If p=0, both sides are clearly equal, so assume p≠0, and we can (by cancellation) simply prove:
(−1)(−1)mn=(−1)n.
It should be clear that if m is even, we have equality (both sides are (−1)n), so we are down to the case where m is odd. In this case:
(−1)(−1)mn=(−1)−n=1(−1)n
Multiplying both sides by (−1)n then yields:
1=(−1)2n=[(−1)n]2 which is always true, no matter what n is
