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OverLord2011 [107]
3 years ago
10

Stefano accidentally dropped his sunglasses off the edge of a canyon as he was looking down. The height, h(t), in meters (as it

relates to sea level), of the sunglasses after t seconds, is shown in the table.
A 2-column table with 8 rows titled Height of Sunglasses Over Time. The first column is labeled t with entries 0, 1, 2, 3, 4, 5, 6, 7. The second column is labeled h(t) with entries 10, 5.1, negative 9.6, negative 34.1, negative 68.4, negative 112.5, negative 166.4, negative 230.1.

During its descent, the pair of sunglasses passed by a climber in the canyon 6 seconds after Stefano dropped them. To the nearest meter, what is difference in elevation between Stefano and the climber?

166 meters
176 meters
230 meters
240 meters
Mathematics
2 answers:
jek_recluse [69]3 years ago
9 0

Answer:

B. 176 meters

Step-by-step explanation:

I took it on EDGE

arsen [322]3 years ago
7 0
176 meters

Stefano is at +10 elevation while the hiker is at -166.4 elevation. The difference would be 10 - (-166.4) = 10 + 166.4 = 176.4 or approximately 176 meters
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a) The 99% confidence interval would be given by (24.409;24.979)  

b) n=464

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Part a

The confidence interval for the mean is given by the following formula:  

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n-1=47-1=46  

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,46)".And we see that t_{\alpha/2}=2.01  

Now we have everything in order to replace into formula (1):  

525-2.01\frac{75}{\sqrt{47}}=503.01  

525+2.01\frac{75}{\sqrt{47}}=546.99  

So on this case the 95% confidence interval would be given by (503.01;546.99)

Part b

The margin of error is given by this formula:  

ME=t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

And on this case we have that ME =7 msec, we are interested in order to find the value of n, if we solve n from equation (1) we got:  

n=(\frac{t_{\alpha/2} s}{ME})^2 (2)  

The critical value for 95% of confidence interval is provided, t_{\alpha/2}=2.01 from part a, replacing into formula (2) we got:  

n=(\frac{2.01(75)}{7})^2 =463.79 \approx 464  

So the answer for this case would be n=464 rounded up to the nearest integer  

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