These are the steps, with their explanations and conclusions:
1) Draw two triangles: ΔRSP and ΔQSP.
2) Since PS is perpendicular to the segment RQ, ∠ RSP and ∠ QSP are equal to 90° (congruent).
3) Since S is the midpoint of the segment RQ, the two segments RS and SQ are congruent.
4) The segment SP is common to both ΔRSP and Δ QSP.
5) You have shown that the two triangles have two pair of equal sides and their angles included also equal, which is the postulate SAS: triangles are congruent if any pair of corresponding sides and their included angles are equal in both triangles.
Then, now you conclude that, since the two triangles are congruent, every pair of corresponding sides are congruent, and so the segments RP and PQ are congruent, which means that the distance from P to R is the same distance from P to Q, i.e. P is equidistant from points R and Q
Shawndra is correct
She made two statements, and both are true:
1. It is not possible to draw a trapezoid that is a
rectangle.
This is true because a trapezoid<span> is a quadrilateral that has exactly one pair of
parallel sides, whereas a rectangle is a parallelogram (i.e. it has two
pairs of parallel sides)</span>
2. It is possible to draw a square that is a rectangle.
This is true because a rectangle refers to any parallelogram
with right angles. A square is also a parallelogram (has two pairs of opposite
sides) with right angles. In fact, all squares are rectangles; only that they
are a special kind of rectangle, where all the sides are equal in length.
Answer:
The answer is A.
Step-by-step explanation:
Hope this helped! :)
Answer: V 3
Step-by-step explanation:
