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MAVERICK [17]
2 years ago
11

(08.01 MC)

Mathematics
1 answer:
Brilliant_brown [7]2 years ago
3 0

Answer:

d. 72 in³

Step-by-step explanation:

To find the volume of  a cylinder that a cone of volume 24 cubic inches fits in exactly inside of, we will follow the steps below:

From the question volume of the cone = 24 cubic inches

volume of a cone = \frac{1}{3} πr²h

and volume of a cylinder = πr²h

This implies

volume of a cone = \frac{1}{3} πr²h

                            = \frac{1}{3} (volume of a cylinder)

volume of a cone =  \frac{1}{3} (volume of a cylinder)

24  =  \frac{1}{3} (volume of a cylinder)

multiply both-side of the equation by 3

24×3 =   \frac{1}{3} (volume of a cylinder)

72  =volume of a cylinder

Therefore volume of the cylinder that the cone fits exactly inside of is  72 cubic inches

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The triangle has size with the lengths of 3 cm 13 cm and 14 cm Is it a right triangle?
WITCHER [35]

Answer:

No, it is not a right triangle

Step-by-step explanation:

Let H = 14 cm

B = 3 cm

P = 13 cm

According to pythagoras theorem:

H^2 = P^2 + B^2

14^2 = 13^2 + 3^2

196 = 169 + 9

196 is not equal to 178

Hence, it is not a right triangle

6 0
3 years ago
Could somebody check my work and tell me if it's right? If its wrong, please tell me where I went wrong.
vodka [1.7K]

Answer:

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4 0
3 years ago
Sanya has a piece of land which is in the shape of a rhombus. She wants her one daughter and one son to work on the land and pro
Neporo4naja [7]

{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

★ Sanya has a piece of land which is in the shape of a rhombus.

★ She wants her one daughter and one son to work on the land and produce different crops, for which she divides the land in two equal parts.

★ Perimeter of land = 400 m.

★ One of the diagonal = 160 m.

{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

★ Area each of them [son and daughter] will get.

{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

Let, ABCD be the rhombus shaped field and each side of the field be x

[ All sides of the rhombus are equal, therefore we will let the each side of the field be x ]

Now,

• Perimeter = 400m

\longrightarrow  \tt AB+BC+CD+AD=400m

\longrightarrow  \tt x + x + x + x=400

\longrightarrow  \tt 4x=400

\longrightarrow  \tt  \: x =  \dfrac{400}{4}

\longrightarrow  \tt x= \red{100m}

\therefore Each side of the field = <u>100m</u><u>.</u>

Now, we have to find the area each [son and daughter] will get.

So, For \triangle ABD,

Here,

• a = 100 [AB]

• b = 100 [AD]

• c = 160 [BD]

\therefore \tt Simi \:  perimeter \:  [S] =  \boxed{ \sf \dfrac{a + b + c}{2} }

\longrightarrow \tt S = \dfrac{100 + 100 + 160}{2}

\longrightarrow \tt S =  \cancel{ \dfrac{360}{2}}

\longrightarrow \tt S = 180m

Using <u>herons formula</u><u>,</u>

\star \tt Area  \: of  \: \triangle = \boxed{\bf{{ \sqrt{s(s - a)(s - b)(s - c) } }}} \star

where

• s is the simi perimeter = 180m

• a, b and c are sides of the triangle which are 100m, 100m and 160m respectively.

<u>Putt</u><u>ing</u><u> the</u><u> values</u><u>,</u>

\longrightarrow \tt  Area_{ ( \triangle \:  ABD)} =  \tt \sqrt{180(180 - 100)(180 - 100)(180 - 160) }

\longrightarrow \tt  Area_{ ( \triangle \:  ABD)} =  \tt \sqrt{180(80)(80)(20) }

\longrightarrow \tt  Area_{ ( \triangle \:  ABD)} =  \tt \sqrt{180 \times 80 \times 80 \times 20 }

\longrightarrow \tt  Area_{ ( \triangle \:  ABD)} =  \tt \sqrt{9 \times 20 \times 20 \times 80 \times 80}

\longrightarrow \tt  Area_{ ( \triangle \:  ABD)} =  \tt \sqrt{ {3}^{2} \times  {20}^{2}  \times  {80}^{2}  }

\longrightarrow \tt  Area_{ ( \triangle \:  ABD)} =  3 \times 20 \times 80

\longrightarrow \tt  Area_{ ( \triangle \:  ABD)} = \red{   4800  \: {m}^{2} }

Thus, area of \triangle ABD = <u>4800 m²</u>

As both the triangles have same sides

So,

Area of \triangle BCD = 4800 m²

<u>Therefore, area each of them [son and daughter] will get = 4800 m²</u>

{\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}

★ Figure in attachment.

{\underline{\rule{290pt}{2pt}}}

7 0
1 year ago
Read 2 more answers
Which statements are true of functions? Check all that apply.
IRINA_888 [86]
Where the rest of the question?
7 0
3 years ago
1. Select all values of x that are solutions to the equation: -2(x + 4)(3x - 18) = 0A) -6B) -4C) -2D) OE) 2F) 4G) 6
navik [9.2K]
\begin{gathered} -2(x+4)(3x-18)=0 \\ \text{There are two factors here which are} \\ -2(x+4)\text{ and} \\ (3x-18) \\ \text{This means, either} \\ 2(x+4)=0 \\ 2x+8=0 \\ 2x=-8 \\ \text{Divide both sides by 2} \\ x=-4 \\ OR \\ 3x-18=0 \\ 3x=18 \\ \text{Divide both sides by 3} \\ x=6 \\ \text{Therefore,} \\ x=-4\text{ or} \\ x=6 \end{gathered}

x = -4 OR x = 6

The correct options are B and G

6 0
1 year ago
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