Answer:
C. (3x2 - 10) (x - 2)
Step-by-step explanation:
3x^2 - 16x +20
Step 1: Sum = - 16x
Product = 60x^2
Step 2: Find 2 numbers that their sum is -16 and their product is 60. If you do that correctly, then you will get two numbers: 10 and -6
Step 3: Replace -16x with the two numbers found in step 2, then you will have; 3x^2 - 6x - 10x + 20
Step 4: Factorise the equation in step 3, like so;
(3x^2 - 6x)(- 10x + 20)
3x(x - 2) -10(x - 2)
(3x - 10)(x - 2)
To check if the answer is correct, expand the bracket: (3x - 10)(x - 2)
If the bracket is opened properly, you will get 3x^2 - 16x + 20
Sure, that's easy! Here's one
5x + 7 = 162
If I wanted to solve this equation, I would break it down. I'd subtract the result (162) by 7
162 - 7 = 155.
From there I just divide that by 5!
155 / 5 = 31
There it is! Ultimate proof that x is in fact 31!
Answer:
<u>y = w and ΔABC ~ ΔCDE</u>
Step-by-step explanation:
Given sin(y°) = cos(x°)
So, ∠y + ∠x = 90° ⇒(1)
And as shown at the graph:
ΔABC is aright triangle at B
So, ∠y + ∠z = 90° ⇒(2)
From (1) and (2)
<u>∴ ∠x = ∠z </u>
ΔCDE is aright triangle at D
So, ∠x + ∠w = 90° ⇒(3)
From (1) and (3)
<u>∴ ∠y = ∠w</u>
So, for the triangles ΔABC and ΔCDE
- ∠A = ∠C ⇒ proved by ∠y = ∠w
- ∠B = ∠D ⇒ Given ∠B and ∠D are right angles.
- ∠C = ∠E ⇒ proved by ∠x = ∠z
So, from the previous ΔABC ~ ΔCDE by AAA postulate.
So, the answer is <u>y = w and ΔABC ~ ΔCDE</u>
Answer:
Step-by-step explanation:
