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Bingel [31]
3 years ago
14

If x =-4 and y= 3 , what is the value of x - 3y^2 ? A. -13 B. -23 C. -31 D. -85

Mathematics
1 answer:
Elanso [62]3 years ago
7 0

Answer:

-31

Step-by-step explanation:

= x - 3y^2

= -4 - 3 × 3^2

= -4 - 27

= -31

hope it helps!

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Probability and Two-Way Tables
alisha [4.7K]

 A and X are two independent events  , Option A is the correct answer.

<h3>When is Probability ?</h3>

Probability is the likelihood of an event to happen

A two way table is given

The two events will be independent when

If A is the first event and B is the second event , then

P(A) = P(A|B)

Here the P(A) = 30/100 = 0.3

P(B) = 20/100 = 0.2

P(A|X) = 15/50 = 0.3

P(A) = P(A|X)

Therefore A and X are two independent events , Option A is the correct answer.

To know more about Probability

brainly.com/question/11234923

#SPJ1

5 0
2 years ago
Read 2 more answers
O<br> Find the equation of the following line
velikii [3]

Answer:

The equation of a line is typically written as y=mx+b where m is the slope and b is the y-intercept.

Step-by-step explanation:

If you know two points that a line passes through, this page will show you how to find the equation of the line.

3 0
3 years ago
7x-4(6-x)+12 if x = 6
aev [14]

Answer:

54

Step-by-step explanation:

7(6)-4(6-6)+12

42-0+12

54

5 0
3 years ago
What is the value of x?
vitfil [10]

Answer:

5 cm

Step-by-step explanation:

We know these are similar triangles, so we can use ratios of side lengths

x/40 = 4/32

Using cross products

32x = 4*40

32x = 160

Divide each side by 32

32x/32 = 160/32

x =5

3 0
3 years ago
The heights of 18-year-old men are approximately normally distributed with mean 68 inches and standard deviation 3 inches. What
Nutka1998 [239]

Answer:

The probability that an 18-year-old man selected at random is greater than 65 inches tall is 0.8413.

Step-by-step explanation:

We are given that the heights of 18-year-old men are approximately normally distributed with mean 68 inches and a standard deviation of 3 inches.

Let X = <u><em>heights of 18-year-old men.</em></u>

So, X ~ Normal(\mu=68,\sigma^{2} =3^{2})

The z-score probability distribution for the normal distribution is given by;

                              Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = mean height = 68 inches

           \sigma = standard deviation = 3 inches

Now, the probability that an 18-year-old man selected at random is greater than 65 inches tall is given by = P(X > 65 inches)

       P(X > 65 inches) = P( \frac{X-\mu}{\sigma} > \frac{65-68}{3} ) = P(Z > -1) = P(Z < 1)

                                                                = <u>0.8413</u>

The above probability is calculated by looking at the value of x = 1 in the z table which has an area of 0.8413.

6 0
3 years ago
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