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3 years ago

10TH GRADE GEOMETRY PLEASE HELP ME!

Mathematics

2 answers:

fredd [130]3 years ago

7 0

The Figures that are shown in the diagram are
Ray CD
and
Segment CD

anygoal [31]3 years ago

5 0

Answer:

B: point D

C: ray CD

E: segment CD

Options 2,3, and 5

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Point Z on a coordinate grid is at (-1,3). If the point is reflected across the line y=-x, what are the coordinates of its image

Neko [114]

(-3,1)

x,y > -y,-x

Therefore (-1,3) is (-3,1)

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4 years ago

Answer this plz<br> find 7%of£40

posledela

£2.8

7% of £40 is £2.8

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3 years ago

If y = x² - 6x + 11 is written in the form y = a ( x - h )² + k, find the value of ( a + h + k).

Crazy boy [7]

Answer:

Step-by-step explanation:

y = x² - 6x + 11

Complete the square.

y = x² - 6x + 9 + 2

y = (x - 3)² + 2

a = 1, h = 3, k = 2

a + h + k = 6

4 0

3 years ago

Read 2 more answers

Should it be facing left or right ?

riadik2000 [5.3K]

Answer:

Facing Right

Step-by-step explanation:

Given inequalities are:

4-x≤-1

Subtracting 4 from both sides

4-x-4≤-1-4

-x≤-5

Multiplying both sides with -1. Multiplying with a negative number changes the sign of the inequality

So,

x≥5

Second Inequality:

2+3x≥17

Subtracting 2 from both sides

2+3x-2≥17-2

3x≥15

Dividing both sides by 3

x≥5

Union of both solutions:

x≥5 ∩ x≥5

=> x≥5

Hence the solution will be facing right on the number line towards all numbers greater than or equals to 5 ..

3 0

3 years ago

A mirror is 24 inches high and 28 inches wide. The center of the mirror will hang 514 feet from the floor on a wall that is 8 fe

Vanyuwa [196]

The distance from the top of the mirror to the ceiling once the mirror is hung on the wall is 21 inches

The dimension of the mirror is given as:

$Height = 24\ in$

$Width = 28\ in$

From the center of the mirror to the floor of the wall, the distance is:

$Distance =5\frac14\ ft$

So, the distance to the top of the mirror will be:

$Top = 5\frac 14\ ft + \frac 12 \times Height$

Substitute 24 for height

$Top = 5\frac 14\ ft+ \frac 12 \times 24\ in$

$Top = 5\frac 14\ ft+ 12 \ in$

Convert feet to inches

$Top = 5\frac 14\times 12\ in+ 12 \ in$

$Top = 63\ in+ 12 \ in$

$Top = 75 \ in$

The distance from the top of the mirror to the ceiling is the difference between the height of the wall and 75 inches.

So, we have:

$Distance = 8\ ft - 75\ in$

Convert feet to inches

$Distance = 8\times 12\ in - 75\ in$

$Distance = 96\ in - 75\ in$

$Distance = 21\ in$

Hence, the distance is 21 inches